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QuestionSolve the equation 3x−4y=−83x - 4y = -8 for yy when x=−4,0,4x = -4, 0, 4.

Studdy Solution

STEP 1

Assumptions1. The equation given is linear 3x−4y=−83x -4y = -8 . We are given three values of xx: -4,0, and43. We need to find the corresponding yy values for these xx values

STEP 2

First, we need to isolate yy in the given equation. We can do this by adding 4y4y to both sides and then dividing by −4-4.
y=x+84y = \frac{x +8}{4}

STEP 3

Now, plug in the first value of xx (-) into the equation to find the corresponding yy value.
y=3(−)+8y = \frac{3(-) +8}{}

STEP 4

implify the equation to find the yy value.
y=−12+84=−44=−1y = \frac{-12 +8}{4} = \frac{-4}{4} = -1So, when x=−4x = -4, y=−1y = -1.

STEP 5

Next, plug in the second value of xx (0) into the equation to find the corresponding yy value.
y=3(0)+84y = \frac{3(0) +8}{4}

STEP 6

implify the equation to find the yy value.
y=0+84=84=2y = \frac{0 +8}{4} = \frac{8}{4} =2So, when x=0x =0, y=2y =2.

STEP 7

Finally, plug in the third value of xx (4) into the equation to find the corresponding yy value.
y=3(4)+4y = \frac{3(4) +}{4}

STEP 8

implify the equation to find the yy value.
y=12+84=204=5y = \frac{12 +8}{4} = \frac{20}{4} =5So, when x=4x =4, y=5y =5.
The completed table is\begin{tabular}{|r|r|} \hlinexx & yy \\ \hline-4 & -1 \\ \hline0 &2 \\ \hline4 &5 \\ \hline\end{tabular}

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