Math

QuestionSolve the inequality 3x+3x+63x + 3 \geq x + 6 and express the solution in interval notation.

Studdy Solution

STEP 1

Assumptions1. We are given the inequality 3x+3x+63x +3 \geq x +6. . We need to solve this inequality for xx.
3. The solution should be written in interval notation.

STEP 2

First, we need to simplify the inequality. We can do this by subtracting xx from both sides of the inequality.
x+xx+6xx + - x \geq x +6 - x

STEP 3

implify the inequality.
2x+362x +3 \geq6

STEP 4

Next, subtract3 from both sides of the inequality to isolate 2x2x on the left side.
2x+33632x +3 -3 \geq6 -3

STEP 5

implify the inequality.
2x32x \geq3

STEP 6

Finally, divide both sides of the inequality by2 to solve for xx.
2x232\frac{2x}{2} \geq \frac{3}{2}

STEP 7

implify to find the solution for xx.
x32x \geq \frac{3}{2}This inequality means that xx is greater than or equal to 32\frac{3}{2}.

STEP 8

To write the solution in interval notation, we use a square bracket to indicate that the endpoint is included in the solution set (since xx can be equal to 32\frac{3}{2}), and we use a parenthesis to indicate that the solution set extends to infinity.
x[32,)x \in \left[\frac{3}{2}, \infty\right)So, the solution to the inequality 3x+3x+63x +3 \geq x +6 is x[32,)x \in \left[\frac{3}{2}, \infty\right).

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