Math  /  Algebra

Question32) (24i)(24i)(2-4 i)(-2-4 i)

Studdy Solution

STEP 1

1. We are asked to find the product of two complex numbers.
2. The expression involves complex numbers in the form a+bi a + bi .
3. The multiplication of complex numbers follows the distributive property, similar to binomials.

STEP 2

1. Apply the distributive property to multiply the complex numbers.
2. Simplify the expression by combining like terms.
3. Use the property i2=1 i^2 = -1 to simplify further.

STEP 3

Apply the distributive property (also known as the FOIL method for binomials) to multiply the complex numbers (24i)(2-4i) and (24i)(-2-4i):
(24i)(24i)=2(2)+2(4i)+(4i)(2)+(4i)(4i)(2-4i)(-2-4i) = 2 \cdot (-2) + 2 \cdot (-4i) + (-4i) \cdot (-2) + (-4i) \cdot (-4i)

STEP 4

Calculate each term:
2(2)=42 \cdot (-2) = -4 2(4i)=8i2 \cdot (-4i) = -8i (4i)(2)=8i(-4i) \cdot (-2) = 8i (4i)(4i)=16i2(-4i) \cdot (-4i) = 16i^2

STEP 5

Combine the terms:
48i+8i+16i2-4 - 8i + 8i + 16i^2
Notice that 8i+8i=0-8i + 8i = 0, so the expression simplifies to:
4+16i2-4 + 16i^2

STEP 6

Use the property i2=1i^2 = -1 to simplify further:
16i2=16(1)=1616i^2 = 16(-1) = -16
Substitute back into the expression:
416=20-4 - 16 = -20
The equivalent value of the expression is:
20\boxed{-20}

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