Math  /  Algebra

Question33-46 - Graphing Piecewise Defined Function of the piecewise defined function.
33. f(x)={0 if x<21 if x2f(x)=\left\{\begin{array}{ll}0 & \text { if } x<2 \\ 1 & \text { if } x \geq 2\end{array}\right.
34. f(x)={1 if x1x+1 if x>1f(x)=\left\{\begin{array}{ll}1 & \text { if } x \leq 1 \\ x+1 & \text { if } x>1\end{array}\right.
35. f(x)={3 if x<2x1 if x2f(x)=\left\{\begin{array}{ll}3 & \text { if } x<2 \\ x-1 & \text { if } x \geq 2\end{array}\right.
36. f(x)={1x if x<25 if x2f(x)=\left\{\begin{array}{ll}1-x & \text { if } x<-2 \\ 5 & \text { if } x \geq-2\end{array}\right.
37. f(x)={x if x0x+1 if x>0f(x)=\left\{\begin{array}{ll}x & \text { if } x \leq 0 \\ x+1 & \text { if } x>0\end{array}\right.
38. f(x)={2x+3 if x<13x if x1f(x)=\left\{\begin{array}{ll}2 x+3 & \text { if } x<-1 \\ 3-x & \text { if } x \geq-1\end{array}\right.
39. f(x)={1 if x<11 if 1x11 if x>1f(x)=\left\{\begin{array}{ll}-1 & \text { if } x<-1 \\ 1 & \text { if }-1 \leq x \leq 1 \\ -1 & \text { if } x>1\end{array}\right.
40. f(x)={1 if x<1x if 1x11 if x>1f(x)=\left\{\begin{array}{ll}-1 & \text { if } x<-1 \\ x & \text { if }-1 \leq x \leq 1 \\ 1 & \text { if } x>1\end{array}\right.

Studdy Solution

STEP 1

What is this asking? We need to graph some funky functions that have different rules depending on the input x\text{x} value! Watch out! Make sure to pay attention to whether the inequalities include the endpoints, that's where those filled and empty circles come in handy!

STEP 2

1. Set up the graph
2. Graph each piece

STEP 3

Let's **draw** our x and y axes, like a cross, giving us four quadrants to work with. **Label** them 'x' and 'y' so we don't forget which is which!

STEP 4

Our function is defined in **two pieces**.
When x<2x < 2, f(x)=0f(x) = 0.
When x2x \geq 2, f(x)=1f(x) = 1.

STEP 5

For x<2x < 2, our function is just a **horizontal line** at y=0y = 0.
Since it's *less than* 2, not *less than or equal to*, we'll put an **open circle** at the point (2,0)(2, 0).

STEP 6

For x2x \geq 2, our function is a **horizontal line** at y=1y = 1.
Since it's *greater than or equal to* 2, we'll use a **filled-in circle** at (2,1)(2, 1).

STEP 7

This time, when x1x \leq 1, f(x)=1f(x) = 1.
When x>1x > 1, f(x)=x+1f(x) = x + 1.

STEP 8

For x1x \leq 1, we have a **horizontal line** at y=1y = 1. **Filled-in circle** at (1,1)(1, 1) because we have *less than or equal to*.

STEP 9

For x>1x > 1, we have f(x)=x+1f(x) = x + 1.
This is a **line** with a **slope** of 1 and a y-intercept of 1.
We'll start an **open circle** at (1,2)(1, 2) and draw the line going up and to the right.

STEP 10

We'll follow the same process for the rest of the problems. **Identify** the pieces, **graph** each piece, and pay close attention to those **endpoints**!
Remember, **open circles** for strict inequalities (<< or >> ) and **filled-in circles** for inequalities that include the endpoint (\leq or \geq ).

STEP 11

We've now graphed all the piecewise functions!
Each graph shows the different pieces of the function, joined together at the specific x-values where the rules change.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord