Math

QuestionCalculate 34(2541)(1730)34 \cdot \begin{pmatrix} 2 & 5 \\ 4 & 1 \end{pmatrix} \cdot \begin{pmatrix} 1 & 7 \\ 3 & 0 \end{pmatrix}.

Studdy Solution

STEP 1

Assumptions1. We are given twox matrices. . We are asked to find the product of these matrices.
3. We are also given a scalar multiple of34.
4. Matrix multiplication is associative, meaning that the order in which the matrices are multiplied does not change the result.

STEP 2

First, we need to multiply the two matrices. The product of two matrices A and B is calculated as followsAB=[a11a12a21a22][b11b12b21b22]=[a11b11+a12b21a11b12+a12b22a21b11+a22b21a21b12+a22b22]A \cdot B = \left[\begin{array}{cc}a_{11} & a_{12} \\ a_{21} & a_{22}\end{array}\right] \cdot \left[\begin{array}{cc}b_{11} & b_{12} \\ b_{21} & b_{22}\end{array}\right] = \left[\begin{array}{cc}a_{11}b_{11} + a_{12}b_{21} & a_{11}b_{12} + a_{12}b_{22} \\ a_{21}b_{11} + a_{22}b_{21} & a_{21}b_{12} + a_{22}b_{22}\end{array}\right]

STEP 3

Now, plug in the given values for the matrices to calculate the product.
[251][1730]\left[\begin{array}{cc}2 &5 \\ &1\end{array}\right] \cdot \left[\begin{array}{cc}1 &7 \\3 &0\end{array}\right]

STEP 4

Calculate the product of the two matrices.
[21+327+041+1347+10]\left[\begin{array}{cc}2*1 +*3 &2*7 +*0 \\4*1 +1*3 &4*7 +1*0\end{array}\right]

STEP 5

implify the matrix multiplication.
[1714728]\left[\begin{array}{cc}17 &14 \\7 &28\end{array}\right]

STEP 6

Now that we have the product of the two matrices, we can multiply this by the scalar multiple of34.
34[171428]34 \cdot \left[\begin{array}{cc}17 &14 \\ &28\end{array}\right]

STEP 7

Calculate the product of the scalar multiple and the matrix.
[341734143473428]\left[\begin{array}{cc}34*17 &34*14 \\34*7 &34*28\end{array}\right]

STEP 8

implify the scalar multiplication.
[578476238952]\left[\begin{array}{cc}578 &476 \\238 &952\end{array}\right]So, 34[2541][1730]=[578476238952]34\left[\begin{array}{ll}2 &5 \\4 &1\end{array}\right]\left[\begin{array}{ll}1 &7 \\3 &0\end{array}\right]=\left[\begin{array}{cc}578 &476 \\238 &952\end{array}\right]

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