Math  /  Algebra

Question3a. 7v3=5+3(v+2)7 v-3=5+3(v+2)

Studdy Solution

STEP 1

What is this asking? Solve for v v in the equation 7v3=5+3(v+2) 7v - 3 = 5 + 3(v + 2) . Watch out! Don't forget to distribute the 3 3 to both terms inside the parentheses!

STEP 2

1. Distribute the 3 3
2. Simplify both sides
3. Isolate v v
4. Solve for v v

STEP 3

Let's **distribute** the 3 3 on the right-hand side of the equation.
We have 3(v+2) 3(v + 2) , which means we need to multiply 3 3 by both v v and 2 2 .
3(v+2)=3v+32=3v+63(v + 2) = 3 \cdot v + 3 \cdot 2 = 3v + 6

STEP 4

Now, **rewrite** the equation with the distributed terms:
7v3=5+3v+67v - 3 = 5 + 3v + 6

STEP 5

**Combine** like terms on the right-hand side.
Add 5 5 and 6 6 together:
7v3=3v+117v - 3 = 3v + 11

STEP 6

Let's **move** all the v v terms to one side and the constants to the other.
Start by subtracting 3v 3v from both sides to get all the v v terms on the left:
7v3v3=117v - 3v - 3 = 11

STEP 7

**Simplify** the left-hand side:
4v3=114v - 3 = 11

STEP 8

Now, **add** 3 3 to both sides to get rid of the constant on the left:
4v=11+34v = 11 + 3

STEP 9

**Simplify** the right-hand side:
4v=144v = 14

STEP 10

Finally, **divide** both sides by 4 4 to solve for v v :
v=144=72v = \frac{14}{4} = \frac{7}{2}

STEP 11

The value of v v is 72\frac{7}{2}.

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