Math  /  Algebra

Question4. a) Explain how you would solve this problem: For what value of nn does the function f(x)=2x2+6xnf(x)=2 x^{2}+6 x-n have only one zero? (1 mark) b) Use your strategy to find the value of nn. (3 marks)

Studdy Solution

STEP 1

1. The function f(x)=2x2+6xnf(x)=2x^2+6x-n is a quadratic function.
2. We need to find the value of nn for which this function has exactly one zero.
3. A quadratic function has one zero when its graph touches the x-axis at exactly one point (i.e., when it has a tangent point with the x-axis).

STEP 2

1. Explain the strategy to solve the problem
2. Apply the strategy to find the value of nn
3. Verify the solution

STEP 3

To solve this problem, we need to consider the discriminant of the quadratic function. The discriminant determines the nature of the roots of a quadratic equation. For a quadratic function to have exactly one zero, its discriminant must be equal to zero. This occurs when the parabola just touches the x-axis at one point.
The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is given by b24acb^2 - 4ac.
Our strategy will be to: a) Identify the coefficients aa, bb, and cc in our function. b) Set up the discriminant equation and set it equal to zero. c) Solve the resulting equation for nn.

STEP 4

Let's apply our strategy:
a) In f(x)=2x2+6xnf(x)=2x^2+6x-n, we can identify: a=2a = 2 b=6b = 6 c=nc = -n
b) Now, let's set up the discriminant equation and set it to zero: b24ac=0b^2 - 4ac = 0 (6)24(2)(n)=0(6)^2 - 4(2)(-n) = 0
c) Solve for nn: 36+8n=036 + 8n = 0 8n=368n = -36 n=368=92=4.5n = -\frac{36}{8} = -\frac{9}{2} = -4.5

STEP 5

To verify our solution, we can substitute n=4.5n = -4.5 back into the original function:
f(x)=2x2+6x(4.5)f(x) = 2x^2 + 6x - (-4.5) f(x)=2x2+6x+4.5f(x) = 2x^2 + 6x + 4.5
Now, if we were to solve this equation, we should get exactly one solution. We can confirm this by looking at the discriminant again:
b24ac=624(2)(4.5)=3636=0b^2 - 4ac = 6^2 - 4(2)(4.5) = 36 - 36 = 0
Since the discriminant is zero, this confirms that the function has exactly one zero when n=4.5n = -4.5.
Therefore, the function f(x)=2x2+6xnf(x)=2x^2+6x-n has only one zero when:
n=4.5\boxed{n = -4.5}

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord