Math  /  Trigonometry

Question4cos2x=34 \cos 2 x=3

Studdy Solution

STEP 1

1. The equation 4cos2x=3 4 \cos 2x = 3 is a trigonometric equation.
2. We will need to isolate the cosine term and use inverse trigonometric functions to solve for x x .

STEP 2

1. Isolate the cosine term cos2x\cos 2x.
2. Solve for 2x2x using the inverse cosine function.
3. Solve for xx.

STEP 3

First, divide both sides of the equation by 4 to isolate the cosine term:
4cos2x=3 4 \cos 2x = 3 cos2x=34 \cos 2x = \frac{3}{4}

STEP 4

Use the inverse cosine function to solve for 2x2x. The general solution for cosθ=a\cos \theta = a is θ=cos1(a)+2kπ\theta = \cos^{-1}(a) + 2k\pi and θ=cos1(a)+2kπ\theta = -\cos^{-1}(a) + 2k\pi, where kk is an integer:
2x=cos1(34)+2kπ 2x = \cos^{-1}\left(\frac{3}{4}\right) + 2k\pi 2x=cos1(34)+2kπ 2x = -\cos^{-1}\left(\frac{3}{4}\right) + 2k\pi

STEP 5

Solve for xx by dividing each part of the equation by 2:
x=12cos1(34)+kπ x = \frac{1}{2} \cos^{-1}\left(\frac{3}{4}\right) + k\pi x=12cos1(34)+kπ x = -\frac{1}{2} \cos^{-1}\left(\frac{3}{4}\right) + k\pi
The general solutions for x x are:
x=12cos1(34)+kπ x = \frac{1}{2} \cos^{-1}\left(\frac{3}{4}\right) + k\pi x=12cos1(34)+kπ x = -\frac{1}{2} \cos^{-1}\left(\frac{3}{4}\right) + k\pi
where k k is an integer.

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