Math

QuestionCalculate the expression using order of operations: 4218÷32×4244^{2}-18 \div 3^{2} \times 4-24.

Studdy Solution

STEP 1

Assumptions1. We are given the expression 418÷3×4244^{}-18 \div3^{} \times4-24 . We need to use the order of operations to solve this expression. The order of operations is Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right). This is often remembered by the acronym PEMAS.

STEP 2

First, we need to perform the operations with exponents in the expression.
42=164^{2} =162=9^{2} =9So, the expression becomes1618÷9×42416 -18 \div9 \times4 -24

STEP 3

Next, we perform the division operation in the expression.
18÷9=218 \div9 =2So, the expression becomes162×2416 -2 \times -24

STEP 4

Next, we perform the multiplication operation in the expression.
2×4=82 \times4 =8So, the expression becomes1682416 -8 -24

STEP 5

Finally, we perform the subtraction operations from left to right.
168=816 -8 =8So, the expression becomes8248 -24

STEP 6

Perform the final subtraction operation.
824=168 -24 = -16So, the value of the given expression is -16.

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