Question4. The ratio of "D"s to "A"s in the school was 8 to 21 . If there were 572 As in the school this term, how many Ds were there? 1502 304 218 1762

Studdy Solution

STEP 1

1. The ratio of "D"s to "A"s is 8 to 21.
2. There are 572 "A"s in the school.
3. We need to find the number of "D"s.

STEP 2

1. Understand the ratio concept.
2. Set up a proportion based on the given ratio.
3. Solve the proportion to find the number of "D"s.

STEP 3

Understand the ratio concept. The ratio 8 to 21 means for every 8 "D"s, there are 21 "A"s.

STEP 4

Set up a proportion. Let $D$ represent the number of "D"s. The ratio can be expressed as:
$\frac{D}{572} = \frac{8}{21}$

STEP 5

Solve the proportion. Cross-multiply to solve for $D$ :
$21D = 8 \times 572$
Calculate the right-hand side:
$21D = 4576$
Divide both sides by 21 to isolate $D$ :
$D = \frac{4576}{21}$
Calculate the division:
$D = 218$
The number of "D"s is:
$\boxed{218}$

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