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Math

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PROBLEM

Solve the inequality 4(5x+3)18x+304(5 x+3) \leq 18 x+30. What are the possible values for xx?

STEP 1

Assumptions1. The given inequality is 4(5x+3)18x+304(5x+3) \leq18x+30
. We need to solve for xx

STEP 2

First, we need to distribute the 44 on the left side of the inequality.
4(5x+)=20x+124(5x+) =20x +12So, the inequality becomes20x+1218x+3020x +12 \leq18x +30

STEP 3

Next, we need to isolate xx by subtracting 18x18x from both sides of the inequality.
20x18x+1218x18x+3020x -18x +12 \leq18x -18x +30This simplifies to2x+12302x +12 \leq30

STEP 4

Then, we subtract 1212 from both sides of the inequality to isolate 2x2x.
2x+121230122x +12 -12 \leq30 -12This simplifies to2x182x \leq18

SOLUTION

Finally, we divide both sides of the inequality by 22 to solve for xx.
2x2182\frac{2x}{2} \leq \frac{18}{2}This simplifies tox9x \leq9So, the solution to the inequality 4(5x+3)18x+304(5x+3) \leq18x+30 is x9x \leq9.

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