Math  /  Calculus

Question5. Find the solution to differential equations dydx+2yx=sin(x)x2\frac{d y}{d x}+\frac{2 y}{x}=\frac{\sin (x)}{x^{2}}

Studdy Solution

STEP 1

What is this asking? We're trying to find a function yy of xx that satisfies the given differential equation.
It's like a puzzle where we have a relationship between the function and its derivative, and we need to figure out what the function is! Watch out! Don't forget to consider the integrating factor, it's the key to unlocking this type of problem!
Also, be careful with your integration and algebra.

STEP 2

1. Identify the Form
2. Find the Integrating Factor
3. Multiply and Integrate
4. Solve for yy

STEP 3

Alright, let's **recognize** that this differential equation is in the form dydx+P(x)y=Q(x)\frac{dy}{dx} + P(x)y = Q(x), which is a **first-order linear differential equation**.
Here, P(x)=2xP(x) = \frac{2}{x} and Q(x)=sin(x)x2Q(x) = \frac{\sin(x)}{x^2}.
Knowing this form is **super important** because it tells us exactly how to approach the problem!

STEP 4

The **integrating factor** is like a magic key!
It's given by eP(x)dxe^{\int P(x) dx}.
So, let's **calculate** it: e2xdx=e2lnx=eln(x2)=x2e^{\int \frac{2}{x} dx} = e^{2 \ln|x|} = e^{\ln(x^2)} = x^2 Remember, we're using the property that aln(b)=ln(ba)a \ln(b) = \ln(b^a) and eln(c)=ce^{\ln(c)} = c.
We can drop the absolute value since we'll be multiplying both sides of the equation by the integrating factor.

STEP 5

Now, we **multiply** both sides of the original differential equation by our **integrating factor**, x2x^2: x2dydx+x22yx=x2sin(x)x2x^2 \frac{dy}{dx} + x^2 \cdot \frac{2y}{x} = x^2 \cdot \frac{\sin(x)}{x^2} This simplifies to: x2dydx+2xy=sin(x)x^2 \frac{dy}{dx} + 2xy = \sin(x)

STEP 6

Notice that the left side is the **derivative** of x2yx^2y with respect to xx.
That's the whole point of the integrating factor!
So, we can rewrite the equation as: ddx(x2y)=sin(x)\frac{d}{dx}(x^2y) = \sin(x)

STEP 7

Now, we **integrate** both sides with respect to xx: ddx(x2y)dx=sin(x)dx\int \frac{d}{dx}(x^2y) dx = \int \sin(x) dx This gives us: x2y=cos(x)+Cx^2y = -\cos(x) + C where CC is the **constant of integration**.
Don't forget that constant!

STEP 8

Finally, we **solve for** yy by dividing both sides by x2x^2: y=cos(x)+Cx2y = \frac{-\cos(x) + C}{x^2} And there we have it!

STEP 9

The solution to the differential equation is y=cos(x)+Cx2y = \frac{-\cos(x) + C}{x^2}.

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