Math  /  Numbers & Operations

Question5. Hydrogen, helium, neon, and argon are all components of a gas mixture. The mixture has a total pressure of 93.6 kPa . Helium, neon, and argon have partial pressures of 15.4kPa,25.7kPa15.4 \mathrm{kPa}, 25.7 \mathrm{kPa}, and 35.6 kPa , respectively. What is the partial pressure exerted by hydrogen in kPa ?

Studdy Solution

STEP 1

1. The total pressure of the gas mixture is 93.6kPa 93.6 \, \text{kPa} .
2. The partial pressures of helium, neon, and argon are 15.4kPa 15.4 \, \text{kPa} , 25.7kPa 25.7 \, \text{kPa} , and 35.6kPa 35.6 \, \text{kPa} , respectively.
3. The partial pressure of hydrogen is the difference between the total pressure and the sum of the partial pressures of helium, neon, and argon.

STEP 2

1. Sum the partial pressures of helium, neon, and argon.
2. Subtract the sum from the total pressure to find the partial pressure of hydrogen.

STEP 3

Calculate the sum of the partial pressures of helium, neon, and argon.
PHe+PNe+PAr=15.4kPa+25.7kPa+35.6kPa P_{\text{He}} + P_{\text{Ne}} + P_{\text{Ar}} = 15.4 \, \text{kPa} + 25.7 \, \text{kPa} + 35.6 \, \text{kPa}
=76.7kPa = 76.7 \, \text{kPa}

STEP 4

Subtract the sum of the partial pressures from the total pressure to find the partial pressure of hydrogen.
PH2=Ptotal(PHe+PNe+PAr) P_{\text{H}_2} = P_{\text{total}} - (P_{\text{He}} + P_{\text{Ne}} + P_{\text{Ar}})
PH2=93.6kPa76.7kPa P_{\text{H}_2} = 93.6 \, \text{kPa} - 76.7 \, \text{kPa}
PH2=16.9kPa P_{\text{H}_2} = 16.9 \, \text{kPa}
The partial pressure exerted by hydrogen is:
16.9kPa\boxed{16.9 \, \text{kPa}}

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