Math

QuestionSimplify the expression 5(ab1)5\left(a b^{-1}\right) using exponent properties and show only positive exponents.

Studdy Solution

STEP 1

Assumptions1. The expression given is 5(ab1)5\left(a b^{-1}\right). We are to simplify the expression using the properties of exponents3. The final answer should only include positive exponents

STEP 2

We start by applying the property of exponents that states an=1/ana^{-n} =1/a^n. This property allows us to rewrite b1b^{-1} as 1/b1/b.
5(ab1)=5(a×1b)5\left(a b^{-1}\right) =5\left(a \times \frac{1}{b}\right)

STEP 3

Next, we apply the distributive property of multiplication over addition, which states that a(b+c)=ab+aca(b + c) = ab + ac. In this case, we are distributing 55 over the terms inside the parenthesis.
5(a×1b)=5a×5b5\left(a \times \frac{1}{b}\right) =5a \times \frac{5}{b}

STEP 4

Finally, we simplify the expression by multiplying the numerical coefficients together.
a×b=25aba \times \frac{}{b} = \frac{25a}{b}So, the simplified form of the given expression with only positive exponents is 25ab\frac{25a}{b}.

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