Math  /  Algebra

Question54. (II) A child on a sled reaches the bottom of a hill with a velocity of 10.0 m/s10.0 \mathrm{~m} / \mathrm{s} and travels 25.0 m along a horizontal straightaway to a stop. If the child and sled together have a mass of 60.0 kg , what is the average retarding force on the sled on the horizontal straightaway?

Studdy Solution

STEP 1

1. The child and sled have an initial velocity of 10.0m/s10.0 \, \text{m/s} at the bottom of the hill.
2. The child and sled come to a stop after traveling 25.0m25.0 \, \text{m} on a horizontal straightaway.
3. The mass of the child and sled together is 60.0kg60.0 \, \text{kg}.
4. We are asked to find the average retarding force on the sled.

STEP 2

1. Identify the known values and the unknown.
2. Use the kinematic equation to find acceleration.
3. Use Newton's second law to find the retarding force.

STEP 3

Identify the known values and the unknown.
- Initial velocity, vi=10.0m/s v_i = 10.0 \, \text{m/s} - Final velocity, vf=0m/s v_f = 0 \, \text{m/s} - Distance traveled, d=25.0m d = 25.0 \, \text{m} - Mass, m=60.0kg m = 60.0 \, \text{kg} - Unknown: Average retarding force, F F

STEP 4

Use the kinematic equation to find acceleration.
The kinematic equation that relates initial velocity, final velocity, acceleration, and distance is:
vf2=vi2+2ad v_f^2 = v_i^2 + 2a d
Substitute the known values:
0=(10.0)2+2a(25.0) 0 = (10.0)^2 + 2a(25.0)
Solve for a a :
0=100+50a 0 = 100 + 50a 50a=100 50a = -100 a=10050 a = -\frac{100}{50} a=2.0m/s2 a = -2.0 \, \text{m/s}^2

STEP 5

Use Newton's second law to find the retarding force.
Newton's second law states:
F=ma F = ma
Substitute the known values:
F=60.0×(2.0) F = 60.0 \times (-2.0) F=120.0N F = -120.0 \, \text{N}
The negative sign indicates that the force is acting in the opposite direction of motion, which is expected for a retarding force.
The average retarding force on the sled is:
120.0N \boxed{-120.0 \, \text{N}}

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