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Math  /  Numbers & Operations

Question6 \longdiv { 1 0 }

Studdy Solution

STEP 1

1. The problem involves the division of two integers.
2. The goal is to find the quotient and remainder of the division.

STEP 2

1. Set up the long division.
2. Perform the division step by step to find the quotient.
3. Determine the remainder.

STEP 3

Set up the long division where 10 is the dividend and 6 is the divisor.
610\begin{array}{r|l} 6 & 10 \\ \end{array}

STEP 4

Determine how many times 6 can go into the first digit of 10.
Since 6 goes into 10 once, place 1 above the division bar.
6  101\begin{array}{r|l} 6 & \; 10 \\ \hline & 1 \\ \end{array}

STEP 5

Multiply 6 by the quotient digit (1) and write the result under 10.
6  10  6\begin{array}{r|l} 6 & \; 10 \\ \hline & \; 6 \\ \end{array}

STEP 6

Subtract 6 from 10 to find the remainder.
10−6=410 - 6 = 4
6  1016‾4\begin{array}{r|l} 6 & \; 10 \\ \hline & 1 \\ & \underline{6} \\ & 4 \\ \end{array}

STEP 7

The quotient is 1 and the remainder is 4.
Thus, the result of the division is: 10÷6=1with a remainder of410 \div 6 = 1 \quad \text{with a remainder of} \quad 4

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