PROBLEM
6. 4sec2θ[cos4θ−1cos8θ−1]=cos2θ எனக் காட்டுக.
STEP 1
1. The given equation involves trigonometric identities.
2. We will use trigonometric identities to simplify and prove the equation.
3. The goal is to manipulate the left-hand side to match the right-hand side, cos2θ.
STEP 2
1. Simplify the fraction inside the brackets.
2. Simplify the overall expression.
3. Prove the equation by matching both sides.
STEP 3
Start by simplifying the fraction inside the brackets. Notice that cos8θ and cos4θ can be expressed using double angle identities. Use the identity for cos2A=2cos2A−1.
For cos8θ, use:
cos8θ=2cos24θ−1 Substitute this into the fraction:
cos4θ−1cos8θ−1=cos4θ−1(2cos24θ−1)−1 =cos4θ−12cos24θ−2 =cos4θ−12(cos24θ−1)
STEP 4
Notice that cos24θ−1 can be factored using the identity cos2A−1=(cosA−1)(cosA+1):
cos24θ−1=(cos4θ−1)(cos4θ+1) Substitute back into the fraction:
cos4θ−12(cos4θ−1)(cos4θ+1) Cancel out (cos4θ−1) from the numerator and denominator:
=2(cos4θ+1)
STEP 5
Substitute the simplified expression back into the original equation:
4sec2θ×2(cos4θ+1)=cos2θ Simplify the expression:
4sec2θ×2cos4θ+4sec2θ×2=cos2θ 2sec2θcos4θ+2sec2θ=cos2θ
STEP 6
Recall that sec2θ=cos2θ1. Substitute this into the equation:
2cos2θcos4θ+2cos2θ1=cos2θ Combine the terms:
2cos2θcos4θ+1=cos2θ
SOLUTION
Multiply both sides by 2cos2θ to eliminate the fraction:
cos4θ+1=2cos22θ Use the identity cos4θ=2cos22θ−1:
2cos22θ−1+1=2cos22θ Both sides are equal, proving the equation.
The equation is verified as true.
Start understanding anything
Get started now for free.