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Math

Math Snap

PROBLEM

6. sec2θ4[cos8θ1cos4θ1]=cos2θ\frac{\sec 2 \theta}{4}\left[\frac{\cos 8 \theta-1}{\cos 4 \theta-1}\right]=\cos 2 \theta எனக் காட்டுக.

STEP 1

1. The given equation involves trigonometric identities.
2. We will use trigonometric identities to simplify and prove the equation.
3. The goal is to manipulate the left-hand side to match the right-hand side, cos2θ\cos 2\theta.

STEP 2

1. Simplify the fraction inside the brackets.
2. Simplify the overall expression.
3. Prove the equation by matching both sides.

STEP 3

Start by simplifying the fraction inside the brackets. Notice that cos8θ\cos 8\theta and cos4θ\cos 4\theta can be expressed using double angle identities. Use the identity for cos2A=2cos2A1\cos 2A = 2\cos^2 A - 1.
For cos8θ\cos 8\theta, use:
cos8θ=2cos24θ1 \cos 8\theta = 2\cos^2 4\theta - 1 Substitute this into the fraction:
cos8θ1cos4θ1=(2cos24θ1)1cos4θ1 \frac{\cos 8\theta - 1}{\cos 4\theta - 1} = \frac{(2\cos^2 4\theta - 1) - 1}{\cos 4\theta - 1} =2cos24θ2cos4θ1 = \frac{2\cos^2 4\theta - 2}{\cos 4\theta - 1} =2(cos24θ1)cos4θ1 = \frac{2(\cos^2 4\theta - 1)}{\cos 4\theta - 1}

STEP 4

Notice that cos24θ1\cos^2 4\theta - 1 can be factored using the identity cos2A1=(cosA1)(cosA+1)\cos^2 A - 1 = (\cos A - 1)(\cos A + 1):
cos24θ1=(cos4θ1)(cos4θ+1) \cos^2 4\theta - 1 = (\cos 4\theta - 1)(\cos 4\theta + 1) Substitute back into the fraction:
2(cos4θ1)(cos4θ+1)cos4θ1 \frac{2(\cos 4\theta - 1)(\cos 4\theta + 1)}{\cos 4\theta - 1} Cancel out (cos4θ1)(\cos 4\theta - 1) from the numerator and denominator:
=2(cos4θ+1) = 2(\cos 4\theta + 1)

STEP 5

Substitute the simplified expression back into the original equation:
sec2θ4×2(cos4θ+1)=cos2θ \frac{\sec 2\theta}{4} \times 2(\cos 4\theta + 1) = \cos 2\theta Simplify the expression:
sec2θ4×2cos4θ+sec2θ4×2=cos2θ \frac{\sec 2\theta}{4} \times 2\cos 4\theta + \frac{\sec 2\theta}{4} \times 2 = \cos 2\theta sec2θcos4θ2+sec2θ2=cos2θ \frac{\sec 2\theta \cos 4\theta}{2} + \frac{\sec 2\theta}{2} = \cos 2\theta

STEP 6

Recall that sec2θ=1cos2θ\sec 2\theta = \frac{1}{\cos 2\theta}. Substitute this into the equation:
cos4θ2cos2θ+12cos2θ=cos2θ \frac{\cos 4\theta}{2\cos 2\theta} + \frac{1}{2\cos 2\theta} = \cos 2\theta Combine the terms:
cos4θ+12cos2θ=cos2θ \frac{\cos 4\theta + 1}{2\cos 2\theta} = \cos 2\theta

SOLUTION

Multiply both sides by 2cos2θ2\cos 2\theta to eliminate the fraction:
cos4θ+1=2cos22θ \cos 4\theta + 1 = 2\cos^2 2\theta Use the identity cos4θ=2cos22θ1\cos 4\theta = 2\cos^2 2\theta - 1:
2cos22θ1+1=2cos22θ 2\cos^2 2\theta - 1 + 1 = 2\cos^2 2\theta Both sides are equal, proving the equation.
The equation is verified as true.

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