Math

QuestionSolve the equation 6(3d+1)40=9d+86(3 d+1)-40=9 d+8 for d.

Studdy Solution

STEP 1

Assumptions1. The equation is 6(3d+1)40=9d+86(3d+1)-40=9d+8 . We need to solve for dd

STEP 2

First, we need to distribute the 66 in the left hand side of the equation.
6(d+1)40=18d+6406(d+1)-40 =18d+6-40

STEP 3

implify the left hand side of the equation.
18d+640=18d3418d+6-40 =18d-34

STEP 4

Now, rewrite the equation with the simplified left hand side.
18d34=9d+818d-34 =9d+8

STEP 5

To isolate dd, we need to get all terms involving dd on one side of the equation and the constants on the other side. First, subtract 9d9d from both sides of the equation.
18d9d34=9d9d+818d-9d-34 =9d-9d+8

STEP 6

implify both sides of the equation.
9d34=89d-34 =8

STEP 7

Next, add 3434 to both sides of the equation to isolate the term with dd.
9d34+34=+349d-34+34 =+34

STEP 8

implify both sides of the equation.
d=42d =42

STEP 9

Finally, divide both sides of the equation by 99 to solve for dd.
d=42/9d =42/9

STEP 10

implify the right hand side of the equation to get the final solution for dd.
d=42/9=14/3d =42/9 =14/3So, d=14/3d =14/3.

Was this helpful?

Studdy solves anything!

banner

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

ParentsInfluencer programContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord