Math

QuestionSolve the system of equations: 7x+3y=07x + 3y = 0 and 5x+10y=0-5x + 10y = 0.

Studdy Solution

STEP 1

Assumptions1. We have a system of two linear equations. . The equations are 7x+3y=07x +3y =0 and 5x+10y=0-5x +10y =0.
3. We are looking for the values of xx and yy that satisfy both equations.

STEP 2

We start by simplifying the second equation. We can do this by dividing the entire equation by 5-5.
5x+10y5=05\frac{-5x +10y}{-5} = \frac{0}{-5}

STEP 3

After simplifying, we getx2y=0x -2y =0This is our new second equation.

STEP 4

Now we have two equations that are easier to work with1. 7x+3y=07x +3y =0
2. x2y=0x -2y =0

STEP 5

Next, we can solve the second equation for xx.
x=2yx =2y

STEP 6

Now we substitute x=2yx =2y into the first equation.
(2y)+3y=0(2y) +3y =0

STEP 7

implify the equation by multiplying 77 by 2y2y.
14y+3y=014y +3y =0

STEP 8

Combine like terms.
17y=017y =0

STEP 9

To find the value of yy, divide both sides of the equation by 1717.
y=17y = \frac{}{17}

STEP 10

implify to get the value of yy.
y=0y =0

STEP 11

Now that we have y=0y =0, we can substitute this into the equation x=yx =y.
x=(0)x =(0)

STEP 12

implify to get the value of xx.
x=0x =0So, the solution to the system of equations is x=0x =0 and y=0y =0.

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