Math  /  Geometry

QuestionS
8. Given: DEHG,DE//GH\overline{\mathrm{DE}} \cong \overline{\mathrm{HG}}, \mathrm{DE} / / \mathrm{GH}

Prove: DFHF\overline{\mathrm{DF}} \cong \overline{\mathrm{HF}} \begin{tabular}{|l|l|} \hline Statement & Reason \\ \hline & \\ \hline & \\ \hline & \\ \hline & \\ \hline & \\ \hline & \\ \hline \end{tabular}

Studdy Solution

STEP 1

1. Line segments DE\overline{\mathrm{DE}} and HG\overline{\mathrm{HG}} are congruent.
2. Line segments DE\mathrm{DE} and GH\mathrm{GH} are parallel.
3. F\mathrm{F} is the intersection point of lines DG\mathrm{DG} and EH\mathrm{EH}.

STEP 2

1. Identify corresponding angles.
2. Use the properties of parallel lines.
3. Apply the Side-Angle-Side (SAS) Congruence Theorem.
4. Conclude congruence of DF\overline{\mathrm{DF}} and HF\overline{\mathrm{HF}}.

STEP 3

Identify corresponding angles formed by the intersecting lines and parallel lines:
- Since DEGH\mathrm{DE} \parallel \mathrm{GH} and DF\mathrm{DF} is a transversal, EDFGHF\angle \mathrm{EDF} \cong \angle \mathrm{GHF} (Alternate Interior Angles).

STEP 4

Use the properties of parallel lines to establish angle congruence:
- DEFHGF\angle \mathrm{DEF} \cong \angle \mathrm{HGF} because they are corresponding angles.

STEP 5

Apply the Side-Angle-Side (SAS) Congruence Theorem:
- We have DEHG\overline{\mathrm{DE}} \cong \overline{\mathrm{HG}}, EDFGHF\angle \mathrm{EDF} \cong \angle \mathrm{GHF}, and DEFHGF\angle \mathrm{DEF} \cong \angle \mathrm{HGF}. - By SAS, DEFHGF\triangle \mathrm{DEF} \cong \triangle \mathrm{HGF}.

STEP 6

Conclude congruence of DF\overline{\mathrm{DF}} and HF\overline{\mathrm{HF}}:
- Since DEFHGF\triangle \mathrm{DEF} \cong \triangle \mathrm{HGF}, corresponding parts of congruent triangles are congruent (CPCTC), so DFHF\overline{\mathrm{DF}} \cong \overline{\mathrm{HF}}.
The proof is complete, and DFHF\overline{\mathrm{DF}} \cong \overline{\mathrm{HF}}.

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