Math  /  Algebra

Question8. If the rotation angle θ=5π2\theta=\frac{5 \pi}{2} radians and the angular speed ω=5π16\omega=\frac{5 \pi}{16} radians per minute, find the rotation time tt in minut
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Studdy Solution

STEP 1

What is this asking? How long does it take to rotate 5π2\frac{5\pi}{2} radians if you're rotating at a speed of 5π16\frac{5\pi}{16} radians per minute? Watch out! Make sure your units match up – we're dealing with radians and minutes here!

STEP 2

1. Set up the relationship between angle, angular speed, and time.
2. Solve for time.

STEP 3

Remember the core relationship: *angle* equals *angular speed* multiplied by *time*.
Think of it like distance equals speed multiplied by time, but for angles!
We can write this as: θ=ωt\theta = \omega \cdot t Where: θ\theta is the rotation angle, ω\omega is the angular speed, and tt is the time.

STEP 4

We know θ=5π2\theta = \frac{5\pi}{2} radians and ω=5π16\omega = \frac{5\pi}{16} radians per minute.
Let's **plug these values** into our formula: 5π2=5π16t\frac{5\pi}{2} = \frac{5\pi}{16} \cdot t

STEP 5

We want to get *t* by itself.
To do this, we can **multiply both sides** of the equation by the reciprocal of 5π16\frac{5\pi}{16}, which is 165π\frac{16}{5\pi}.
This is like dividing both sides by 5π16\frac{5\pi}{16}, but thinking about it as multiplying by the reciprocal helps us see how things simplify nicely! 165π5π2=165π5π16t\frac{16}{5\pi} \cdot \frac{5\pi}{2} = \frac{16}{5\pi} \cdot \frac{5\pi}{16} \cdot t

STEP 6

On the right side, 165π5π16\frac{16}{5\pi} \cdot \frac{5\pi}{16} becomes 1, effectively isolating *t*.
On the left side, the π\pi and 55 in the numerator and denominator divide to one, leaving us with: 162=t\frac{16}{2} = t

STEP 7

Finally, we **divide 16 by 2** to get our **final answer**: t=8t = 8

STEP 8

The rotation time tt is **8 minutes**.

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