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Math

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PROBLEM

Solve the equations: 8x1=2x338^{x-1}=\sqrt[3]{2^{x-3}} and 35x+5x+1=8533 \cdot 5^{x}+5^{x+1}=8 \cdot 5^{3}.

STEP 1

Assumptions1. We are given two equations, 8x1=x338^{x-1}=\sqrt[3]{^{x-3}} and 35x+5x+1=8533 \cdot5^{x}+5^{x+1}=8 \cdot5^{3}.
. We are assuming that the base of the exponentials and radicals are positive real numbers.
3. We are assuming that the exponent x is a real number.

STEP 2

Let's start with the first equation 8x1=2x8^{x-1}=\sqrt[]{2^{x-}}. We can rewrite8 and2 in terms of the same base to simplify the equation.
8 =2^So, the equation becomes(2^)^{x-1}=\sqrt[]{2^{x-}}

STEP 3

Apply the power of a power rule in the left side of the equation. This rule states that (am)n=amn(a^m)^n = a^{mn}.
23(x1)=2x332^{3(x-1)}=\sqrt[3]{2^{x-3}}

STEP 4

The cube root can be written as a power of one-third. So, the equation becomes23(x1)=2x332^{3(x-1)}=2^{\frac{x-3}{3}}

STEP 5

Since the bases are the same, we can set the exponents equal to each other. This gives us our first equation in x.
3(x1)=x333(x-1)=\frac{x-3}{3}

STEP 6

Now, let's solve the equation for x. First, multiply both sides of the equation by3 to get rid of the fraction.
9(x1)=x39(x-1)=x-3

STEP 7

Expand the left side and simplify the equation.
9x9=x39x -9 = x -3

STEP 8

Subtract x from both sides of the equation.
8x=38x - = -3

STEP 9

Add9 to both sides of the equation.
8x=68x =6

STEP 10

Finally, divide both sides of the equation by8 to solve for x.
x=68=34x = \frac{6}{8} = \frac{3}{4}

STEP 11

Now, let's solve the second equation 35x+5x+=8533 \cdot5^{x}+5^{x+}=8 \cdot5^{3}. We can simplify the equation by dividing both sides by 535^3.
35x53+5x+53=8\frac{3 \cdot5^{x}}{5^3}+\frac{5^{x+}}{5^3}=8

STEP 12

implify the equation using the rule amn=amana^{m-n} = \frac{a^m}{a^n}.
5x+5x=8 \cdot5^{x-}+5^{x-}=8

STEP 13

Since x=3x = \frac{3}{}, substitute 3\frac{3}{} for x in the equation.
3533+533=83 \cdot5^{\frac{3}{}-3}+5^{\frac{3}{}-3}=8

STEP 14

implify the equation.
394+94=83 \cdot^{-\frac{9}{4}}+^{-\frac{9}{4}}=8

STEP 15

Multiply both sides of the equation by 5945^{\frac{9}{4}} to get rid of the negative exponent.
3+594=85943 +5^{\frac{9}{4}} =8 \cdot5^{\frac{9}{4}}

STEP 16

Subtract 5945^{\frac{9}{4}} from both sides of the equation.
3=85945943 =8 \cdot5^{\frac{9}{4}} -5^{\frac{9}{4}}

STEP 17

Factor out 5945^{\frac{9}{4}} on the right side of the equation.
3=594()3 =5^{\frac{9}{4}}( -)

STEP 18

implify the right side of the equation.
3=7543 =7 \cdot5^{\frac{}{4}}

STEP 19

Divide both sides of the equation by7.
37=594\frac{3}{7} =5^{\frac{9}{4}}

STEP 20

Take the fourth root of both sides of the equation to solve for 5945^{\frac{9}{4}}.
374=5916\sqrt[4]{\frac{3}{7}} =5^{\frac{9}{16}}

STEP 21

Raise both sides of the equation to the power of16 to solve for5.
(374)16=59\left(\sqrt[4]{\frac{3}{7}}\right)^{16} =5^9

STEP 22

Calculate the left side of the equation.
(74)16=81823543\left(\sqrt[4]{\frac{}{7}}\right)^{16} = \frac{81}{823543}

STEP 23

Set the equation equal to5.
81823543=5\frac{81}{823543} =5

SOLUTION

This equation is not true, so there is no solution to the system of equations.

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