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Math

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PROBLEM

9 Express each of the following as a simplified rate.
a 180 students on 3 buses
b \(\) 5.60$ for 4 kg
c 186 km in 2122 \frac{1}{2} hours
5:25: 2
10 Find the average rate for each situation.
a Thelma drove 8000 km in 50 days
b Callum saved \(\) 1250$ in 6 months
c. Ainslie grew 20 cm in 2122 \frac{1}{2} years
11 Who earns the most, and by how much, if Kelly is paid \(\) 96570ayearandToddearns a year and Todd earns $ 7985$ each month?
Which is faster 70 km/h70 \mathrm{~km} / \mathrm{h} or 21 m/s21 \mathrm{~m} / \mathrm{s} ?

STEP 1

1. We are asked to express given quantities as simplified rates.
2. We need to find average rates for given situations.
3. We need to compare earnings to determine who earns more.
4. We need to compare speeds in different units to determine which is faster.

STEP 2

1. Simplify given rates.
2. Calculate average rates.
3. Compare earnings.
4. Compare speeds.

STEP 3

a. Simplify the rate of students per bus.
180 students3 buses=1803=60 students per bus\frac{180 \text{ students}}{3 \text{ buses}} = \frac{180}{3} = 60 \text{ students per bus}

STEP 4

b. Simplify the rate of dollars per kilogram.
\frac{\($\)5.60}{4 \text{ kg}} = \frac{5.60}{4} = \($\)1.40 \text{ per kg}

STEP 5

c. Simplify the rate of kilometers per hour.
Convert 2122 \frac{1}{2} hours to an improper fraction: 2.52.5 hours.
186 km2.5 hours=1862.5=74.4 km per hour\frac{186 \text{ km}}{2.5 \text{ hours}} = \frac{186}{2.5} = 74.4 \text{ km per hour}

STEP 6

d. Simplify the ratio 5:25:2.
The ratio 5:25:2 is already in its simplest form.

STEP 7

a. Find the average rate of kilometers per day for Thelma.
8000 km50 days=800050=160 km per day\frac{8000 \text{ km}}{50 \text{ days}} = \frac{8000}{50} = 160 \text{ km per day}

STEP 8

b. Find the average rate of dollars saved per month for Callum.
\frac{\($\)1250}{6 \text{ months}} = \frac{1250}{6} \approx \($\)208.33 \text{ per month}

STEP 9

c. Find the average rate of growth per year for Ainslie.
Convert 2122 \frac{1}{2} years to an improper fraction: 2.52.5 years.
20 cm2.5 years=202.5=8 cm per year\frac{20 \text{ cm}}{2.5 \text{ years}} = \frac{20}{2.5} = 8 \text{ cm per year}

STEP 10

Compare Kelly's and Todd's earnings.
Kelly earns $96570\$96570 per year.
Todd earns $7985\$7985 per month, so annually he earns:
\($\)7985 \times 12 = \($\)95820 Kelly earns more than Todd by:
\($\)96570 - \($\)95820 = \($\)750

SOLUTION

Compare speeds of 70 km/h70 \text{ km/h} and 21 m/s21 \text{ m/s}.
Convert 70 km/h70 \text{ km/h} to meters per second:
70 km/h=70×1000360019.44 m/s70 \text{ km/h} = \frac{70 \times 1000}{3600} \approx 19.44 \text{ m/s} Since 21 m/s21 \text{ m/s} is greater than 19.44 m/s19.44 \text{ m/s}, 21 m/s21 \text{ m/s} is faster.
The solutions are:
1. Simplified rates:
- 6060 students per bus
- $1.40\$1.40 per kg
- 74.474.4 km per hour
- Ratio 5:25:2
2. Average rates:
- 160160 km per day
- $208.33\$208.33 per month
- 88 cm per year
3. Kelly earns more than Todd by $750\$750.
4. 21 m/s21 \text{ m/s} is faster than 70 km/h70 \text{ km/h}.

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