Math

QuestionConvert these measurements: a. 100 kg=100 \mathrm{~kg}= g, b. 0.000000000001 nm=0.000000000001 \mathrm{~nm}= pm, c. 260HL=260 \mathrm{HL}= mL.

Studdy Solution

STEP 1

Assumptions1. We are converting from one unit of measurement to another. . The conversion factors are as follows a.1 kg =1000 g b.1 nm =1000 pm c.1 HL =100000 mL

STEP 2

For part a, we need to convert kilograms to grams. We can do this by multiplying the given amount in kilograms by the conversion factor.
100kg=100kg×1000g/kg100 \, kg =100 \, kg \times1000 \, g/kg

STEP 3

Calculate the conversion for part a.
100kg=100×1000g=100000g100 \, kg =100 \times1000 \, g =100000 \, g

STEP 4

For part b, we need to convert nanometers to picometers. We can do this by multiplying the given amount in nanometers by the conversion factor.
0.000000000001nm=0.000000000001nm×1000pm/nm0.000000000001 \, nm =0.000000000001 \, nm \times1000 \, pm/nm

STEP 5

Calculate the conversion for part b.
0.000000000001nm=0.000000000001×1000pm=0.000001pm0.000000000001 \, nm =0.000000000001 \times1000 \, pm =0.000001 \, pm

STEP 6

For part c, we need to convert hectoliters to milliliters. We can do this by multiplying the given amount in hectoliters by the conversion factor.
260HL=260HL×100000mL/HL260 \, HL =260 \, HL \times100000 \, mL/HL

STEP 7

Calculate the conversion for part c.
260HL=260×100000mL=26000000mL260 \, HL =260 \times100000 \, mL =26000000 \, mLSo, the conversions area. 100kg=100000g100 \, kg =100000 \, g b. 0.000000000001nm=0.000001pm0.000000000001 \, nm =0.000001 \, pm c. 260HL=26000000mL260 \, HL =26000000 \, mL

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