QuestionFind the minimum selling price of a 6 oz bottle of Oseki Sake with a case cost of \$55.20 and a desired cost of 26.5%.

Studdy Solution

STEP 1

Assumptions1. The cost of a24 bottle case of Osekiake is $55.20. Each bottle is6 oz3. The restaurant uses a26.5% desired beverage cost percent to determine the selling price4. The selling price is calculated per bottle

STEP 2

First, we need to find the cost per bottle. We can do this by dividing the total cost of the case by the number of bottles in the case.
$Cost\, per\, bottle = Total\, cost / Number\, of\, bottles$

STEP 3

Now, plug in the given values for the total cost and number of bottles to calculate the cost per bottle.
$Cost\, per\, bottle = \$55.20 /24$

STEP 4

Calculate the cost per bottle.
$Cost\, per\, bottle = \$55.20 /24 = \$2.30$

STEP 5

Now that we have the cost per bottle, we can find the minimum selling price. This is done by dividing the cost per bottle by the desired beverage cost percent.
$elling\, price = Cost\, per\, bottle / Desired\, beverage\, cost\, percent$

STEP 6

Convert the percentage to a decimal value.
$26.5\% =0.265$

STEP 7

Plug in the values for the cost per bottle and the desired beverage cost percent to calculate the selling price.
$elling\, price = \$2.30 /0.265$

STEP 8

Calculate the minimum selling price for one bottle of sake.
$elling\, price = \$2.30 /0.265 = \$8.68$ The minimum selling price for one bottle of sake must be $8.68.

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