Math

QuestionFind the temperature change of a 25.0 g25.0 \mathrm{~g} brass piece from 325C325^{\circ} \mathrm{C} to 42.0C42.0^{\circ} \mathrm{C}. ΔTbrass =[?]C \Delta \mathrm{T}_{\text {brass }}=[?]^{\circ} \mathrm{C}

Studdy Solution

STEP 1

Assumptions1. The initial temperature of the brass is 325C325^{\circ} \mathrm{C} . The final temperature of the brass is 42.0C42.0^{\circ} \mathrm{C}

STEP 2

The change in temperature is calculated by subtracting the final temperature from the initial temperature.
Δbrass =initialfinal\Delta_{\text {brass }} =_{\text {initial}} -_{\text {final}}

STEP 3

Now, plug in the given values for the initial and final temperatures to calculate the change in temperature.
Δbrass =325C42.0C\Delta_{\text {brass }} =325^{\circ} \mathrm{C} -42.0^{\circ} \mathrm{C}

STEP 4

Calculate the change in temperature.
Δbrass =325C42.0C=283C\Delta_{\text {brass }} =325^{\circ} \mathrm{C} -42.0^{\circ} \mathrm{C} =283^{\circ} \mathrm{C}The change in temperature of the brass is 283C-283^{\circ} \mathrm{C}. The negative sign indicates that the temperature has decreased.

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