QuestionCalculate the number of atoms in a $44.5 \mathrm{~mol}$ sample of $\mathrm{Ne}$ , using correct sig figs and scientific notation.

Studdy Solution

STEP 1

Assumptions1. We are given a sample of Neon (Ne) with a quantity of44.5 mol. . We know that1 mol of any substance contains Avogadro's number of particles (atoms, molecules, etc.), which is approximately $6.022 \times10^{23}$ particles per mol.

STEP 2

We need to find the number of atoms in the given sample. We can do this by multiplying the number of moles by Avogadro's number.
$Number\, of\, atoms = Number\, of\, moles \times Avogadro's\, number$

STEP 3

Now, plug in the given values for the number of moles and Avogadro's number to calculate the number of atoms.
$Number\, of\, atoms =44.5 \, mol \times6.022 \times10^{23} \, atoms/mol$

STEP 4

Perform the multiplication to find the number of atoms.
$Number\, of\, atoms =44. \, mol \times6.022 \times10^{23} \, atoms/mol =2.67979 \times10^{25} \, atoms$

STEP 5

The problem asks for the answer to be given to the correct number of significant figures. The given quantity of44.5 mol has three significant figures, so our answer should also have three significant figures. $Number\, of\, atoms =2.68 \times10^{25} \, atoms$ So, there are $2.68 \times10^{25}$ atoms in a44.5 mol sample of Neon.

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