QuestionFind the empirical formula of a metal sulfide formed from 8.741 g of iron and 13.76 g of product mass.
Studdy Solution
STEP 1
Assumptions1. The initial mass of iron is8.741 g. The final mass of the metal sulfide is13.76 g3. The excess sulfur reacts completely with the iron to form the metal sulfide4. The difference in mass between the metal sulfide and the initial iron sample is the mass of sulfur in the compound
STEP 2
First, we need to find the mass of sulfur in the metal sulfide. We can do this by subtracting the initial mass of iron from the final mass of the metal sulfide.
STEP 3
Now, plug in the given values for the final mass of the metal sulfide and the initial mass of iron to calculate the mass of sulfur.
STEP 4
Calculate the mass of sulfur.
STEP 5
Next, we need to convert the mass of iron and sulfur to moles. We can do this by dividing the mass by the atomic mass. The atomic mass of iron (Fe) is approximately55.85 g/mol, and the atomic mass of sulfur () is approximately32.06 g/mol.
STEP 6
Now, plug in the given values for the mass of iron and sulfur and the atomic masses to calculate the moles of iron and sulfur.
STEP 7
Calculate the moles of iron and sulfur.
STEP 8
To find the empirical formula, we need to find the ratio of moles of iron to moles of sulfur. Since the numbers are very close, we can assume the ratio is11.
STEP 9
Therefore, the empirical formula of the metal sulfide is Fe.
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