Math  /  Algebra

Questionmb A block of mass 3 m can move without friction on a horizontal table. This block is attached to another block of mass mm by a cord that passes over a frictionless pulley, as shown above. If the masses of the cord and the pulley are negligible, what is the magnitude of the acceleration of the descending block? (A) g/4g / 4 (B) g/3g / 3 (C) 2g/32 g / 3 (D) g

Studdy Solution

STEP 1

1. The block of mass 3m3m can move without friction on a horizontal table.
2. The block of mass mm is descending vertically.
3. The cord and pulley are frictionless and have negligible mass.
4. We are tasked with finding the acceleration of the descending block of mass mm.
5. The acceleration due to gravity is gg.

STEP 2

1. Analyze the forces acting on each block.
2. Write the equations of motion for each block.
3. Solve the system of equations to find the acceleration.

STEP 3

Analyze the forces acting on each block.
- For the block of mass 3m3m on the table, the only horizontal force is the tension TT in the cord. - For the descending block of mass mm, the forces are the gravitational force mgmg downward and the tension TT upward.

STEP 4

Write the equations of motion for each block.
- For the block of mass 3m3m on the table: $ 3m \cdot a = T \]
- For the descending block of mass mm: $ m \cdot a = mg - T \]

STEP 5

Solve the system of equations to find the acceleration.
First, solve the equation for the block of mass 3m3m for TT: T=3maT = 3m \cdot a
Substitute T=3maT = 3m \cdot a into the equation for the descending block: ma=mg3mam \cdot a = mg - 3m \cdot a
Combine like terms: ma+3ma=mgm \cdot a + 3m \cdot a = mg 4ma=mg4m \cdot a = mg
Divide both sides by 4m4m to solve for aa: a=mg4ma = \frac{mg}{4m} a=g4a = \frac{g}{4}
The magnitude of the acceleration of the descending block is:
g4 \boxed{\frac{g}{4}}

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