Solve a problem of your own!
Download the Studdy App!

Math

Math Snap

PROBLEM

Calculate the depth of a well if a bucket falls for 9.3 seconds. Round to the nearest tenth. Use d=12gt2d = \frac{1}{2}gt^2.

STEP 1

Assumptions1. The bucket falls freely, meaning it is only affected by gravity and not by any other forces (like air resistance).
. The acceleration due to gravity is approximately 9.8\, m/s^.
3. The bucket starts from rest, meaning its initial velocity is 0m/s0\, m/s.
4. The time of fall is 9.3seconds9.3\, seconds.

STEP 2

We can use the equation of motion to find the depth of the well. The equation of motion is given byd=vit+0.5at2d = v_i t +0.5 a t^2where- dd is the distance (depth of the well),
- viv_i is the initial velocity,
- aa is the acceleration (due to gravity), and- tt is the time.

STEP 3

Now, plug in the given values for the initial velocity, acceleration, and time into the equation of motion.
d=09.3+0.59.8(9.3)2d =0 \cdot9.3 +0.5 \cdot9.8 \cdot (9.3)^2

STEP 4

Calculate the depth of the well.
d=0.9.8(9.3)2=424.435md =0. \cdot9.8 \cdot (9.3)^2 =424.435\, m

SOLUTION

Round the depth of the well to the nearest tenth.
d424.4md \approx424.4\, mThe depth of the well is approximately424.4 meters.

Was this helpful?
banner

Start understanding anything

Get started now for free.

OverviewParentsContactPolicyTerms
TwitterInstagramFacebookTikTokDiscord