QuestionCalculate the cost to drive 150 miles with 23 mpg and gas at 327 cents/gallon. Also, find the cost formula $C(m, g, d)$ . Then, use it for 28 mpg over 188 miles at \$3.77/gallon.

Studdy Solution

STEP 1

Assumptions1. The distance driven is150 miles. The car's gas mileage is23 miles per gallon3. The cost of gasoline is327 cents per gallon4. The cost is calculated as a one-time payment, not per mile

STEP 2

First, we need to find the number of gallons used to drive150 miles. We can do this by dividing the distance by the car's gas mileage.
$Gallons\, used = Distance / Gas\, mileage$

STEP 3

Now, plug in the given values for the distance and gas mileage to calculate the gallons used.
$Gallons\, used =150\, miles /23\, miles\, per\, gallon$

STEP 4

Calculate the gallons used.
$Gallons\, used =150\, miles /23\, miles\, per\, gallon =6.52\, gallons$

STEP 5

Now that we have the gallons used, we can find the total cost. This can be done by multiplying the gallons used by the cost per gallon.
$Cost = Gallons\, used \\times Cost\, per\, gallon$

STEP 6

Plug in the values for the gallons used and the cost per gallon to calculate the total cost.
$Cost =6.52\, gallons \\times327\, cents\, per\, gallon$

STEP 7

Calculate the total cost.
$Cost =6.52\, gallons \\times327\, cents\, per\, gallon =2131.44\, cents$

STEP 8

Convert the cost from cents to dollars.
$Cost =2131.44\, cents = \$21.31$

STEP 9

The cost function $C(m, g, d)$ can be derived from the steps above. It is the product of the distance divided by the car's gas mileage and the cost per gallon.
$C(m, g, d) = \frac{d}{m} \times g$

STEP 10

Now, we can use the cost function to calculate the cost of driving a car that gets28 miles per gallon a distance of188 miles if gasoline costs $3.77 per gallon.
$C(28,3.77,188) = \frac{188}{28} \times3.77$

STEP 11

Calculate the cost.
$C(28,3.77,188) = \frac{188}{28} \times3.77 = \$25.26$ The cost to drive150 miles if your car gets23 miles per gallon and gasoline costs327 cents per gallon is $21.31. The cost function$ C(m, g, d) $is$ \frac{d}{m} \times g $. The cost of driving a car that gets28 miles per gallon a distance of188 miles if gasoline costs$ 3.77 per gallon is $25.26.

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QuestionCalculate the cost to drive 150 miles with 23 mpg and gas at 327 cents/gallon. Also, find the cost formula $C(m, g, d)$ . Then, use it for 28 mpg over 188 miles at \$3.77/gallon.

Studdy Solution

STEP 1

Assumptions1. The distance driven is150 miles. The car's gas mileage is23 miles per gallon3. The cost of gasoline is327 cents per gallon4. The cost is calculated as a one-time payment, not per mile

STEP 2

First, we need to find the number of gallons used to drive150 miles. We can do this by dividing the distance by the car's gas mileage.
$Gallons\, used = Distance / Gas\, mileage$

STEP 3

Now, plug in the given values for the distance and gas mileage to calculate the gallons used.
$Gallons\, used =150\, miles /23\, miles\, per\, gallon$

STEP 4

Calculate the gallons used.
$Gallons\, used =150\, miles /23\, miles\, per\, gallon =6.52\, gallons$

STEP 5

Now that we have the gallons used, we can find the total cost. This can be done by multiplying the gallons used by the cost per gallon.
$Cost = Gallons\, used \\times Cost\, per\, gallon$

STEP 6

Plug in the values for the gallons used and the cost per gallon to calculate the total cost.
$Cost =6.52\, gallons \\times327\, cents\, per\, gallon$

STEP 7

Calculate the total cost.
$Cost =6.52\, gallons \\times327\, cents\, per\, gallon =2131.44\, cents$

STEP 8

Convert the cost from cents to dollars.
$Cost =2131.44\, cents = \$21.31$

STEP 9

The cost function $C(m, g, d)$ can be derived from the steps above. It is the product of the distance divided by the car's gas mileage and the cost per gallon.
$C(m, g, d) = \frac{d}{m} \times g$

STEP 10

Now, we can use the cost function to calculate the cost of driving a car that gets28 miles per gallon a distance of188 miles if gasoline costs $3.77 per gallon.
$C(28,3.77,188) = \frac{188}{28} \times3.77$

STEP 11

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QuestionCalculate the cost to drive 150 miles with 23 mpg and gas at 327 cents/gallon. Also, find the cost formula C(m,g,d)C(m, g, d)C(m,g,d). Then, use it for 28 mpg over 188 miles at \$3.77/gallon.

Studdy Solution

STEP 1

Assumptions1. The distance driven is150 miles. The car's gas mileage is23 miles per gallon3. The cost of gasoline is327 cents per gallon4. The cost is calculated as a one-time payment, not per mile

STEP 2

First, we need to find the number of gallons used to drive150 miles. We can do this by dividing the distance by the car's gas mileage.Gallons used=Distance/Gas mileageGallons\, used = Distance / Gas\, mileageGallonsused=Distance/Gasmileage

STEP 3

Now, plug in the given values for the distance and gas mileage to calculate the gallons used.Gallons used=150 miles/23 miles per gallonGallons\, used =150\, miles /23\, miles\, per\, gallonGallonsused=150miles/23milespergallon

STEP 4

Calculate the gallons used.Gallons used=150 miles/23 miles per gallon=6.52 gallonsGallons\, used =150\, miles /23\, miles\, per\, gallon =6.52\, gallonsGallonsused=150miles/23milespergallon=6.52gallons

STEP 5

Now that we have the gallons used, we can find the total cost. This can be done by multiplying the gallons used by the cost per gallon.Cost=Gallons usedtimesCost per gallonCost = Gallons\, used \\times Cost\, per\, gallonCost=GallonsusedtimesCostpergallon

STEP 6

Plug in the values for the gallons used and the cost per gallon to calculate the total cost.Cost=6.52 gallonstimes327 cents per gallonCost =6.52\, gallons \\times327\, cents\, per\, gallonCost=6.52gallonstimes327centspergallon

STEP 7

Calculate the total cost.Cost=6.52 gallonstimes327 cents per gallon=2131.44 centsCost =6.52\, gallons \\times327\, cents\, per\, gallon =2131.44\, centsCost=6.52gallonstimes327centspergallon=2131.44cents

STEP 8

Convert the cost from cents to dollars.Cost=2131.44 cents=$21.31Cost =2131.44\, cents = \$21.31Cost=2131.44cents=$21.31

STEP 9

The cost function C(m,g,d)C(m, g, d)C(m,g,d) can be derived from the steps above. It is the product of the distance divided by the car's gas mileage and the cost per gallon.C(m,g,d)=dm×gC(m, g, d) = \frac{d}{m} \times gC(m,g,d)=md​×g

STEP 10

Now, we can use the cost function to calculate the cost of driving a car that gets28 miles per gallon a distance of188 miles if gasoline costs $3.77 per gallon.C(28,3.77,188)=18828×3.77C(28,3.77,188) = \frac{188}{28} \times3.77C(28,3.77,188)=28188​×3.77

STEP 11

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QuestionCalculate the cost to drive 150 miles with 23 mpg and gas at 327 cents/gallon. Also, find the cost formula $C(m, g, d)$ . Then, use it for 28 mpg over 188 miles at \$3.77/gallon.

First, we need to find the number of gallons used to drive150 miles. We can do this by dividing the distance by the car's gas mileage.
$Gallons\, used = Distance / Gas\, mileage$

Now, plug in the given values for the distance and gas mileage to calculate the gallons used.
$Gallons\, used =150\, miles /23\, miles\, per\, gallon$

Calculate the gallons used.
$Gallons\, used =150\, miles /23\, miles\, per\, gallon =6.52\, gallons$

Now that we have the gallons used, we can find the total cost. This can be done by multiplying the gallons used by the cost per gallon.
$Cost = Gallons\, used \\times Cost\, per\, gallon$

Plug in the values for the gallons used and the cost per gallon to calculate the total cost.
$Cost =6.52\, gallons \\times327\, cents\, per\, gallon$

Calculate the total cost.
$Cost =6.52\, gallons \\times327\, cents\, per\, gallon =2131.44\, cents$

Convert the cost from cents to dollars.
$Cost =2131.44\, cents = \$21.31$

The cost function $C(m, g, d)$ can be derived from the steps above. It is the product of the distance divided by the car's gas mileage and the cost per gallon.
$C(m, g, d) = \frac{d}{m} \times g$

Now, we can use the cost function to calculate the cost of driving a car that gets28 miles per gallon a distance of188 miles if gasoline costs $3.77 per gallon.
$C(28,3.77,188) = \frac{188}{28} \times3.77$