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QuestionLet the number of ten dollar bills be xx. Then, the number of five dollar bills is 2x2x. Solve for xx given 5(2x)+10(x)=7205(2x) + 10(x) = 720. How many ten's are there?

Studdy Solution

STEP 1

Assumptions1. The cash register contains only five dollar and ten dollar bills. . The number of five dollar bills is twice the number of ten dollar bills.
3. The total amount of money in the cash register is720 dollars.

STEP 2

Let's denote the number of ten dollar bills as x. Then, the number of five dollar bills is2x.

STEP 3

We can write an equation that represents the total amount of money in the cash register. The total amount is the sum of the value of the five dollar bills and the value of the ten dollar bills.
Total amount=Value of five′s+Value of ten′sTotal\, amount = Value\, of\, five's + Value\, of\, ten's

STEP 4

Substitute the values for the number of five's and ten's into the equation. The value of a bill is its face value times the number of such bills.
720=⋅2x+10⋅x720 = \cdot2x +10 \cdot x

STEP 5

implify the equation.
720=10x+10x720 =10x +10x

STEP 6

Combine like terms.
720=20x720 =20x

STEP 7

Now, solve for x by dividing both sides of the equation by20.
x=720/20x =720 /20

STEP 8

Calculate the value of x.
x=720/20=36x =720 /20 =36So, there are36 ten dollar bills in the cash register.

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