Math

QuestionA student needs 65.0 g65.0 \mathrm{~g} of glycerol with a density of 1.26 gcm31.26 \mathrm{~g} \cdot \mathrm{cm}^{-3}. Find the volume.

Studdy Solution

STEP 1

Assumptions1. The student needs65.0 g of glycerol. . The density of glycerol is1.26 g/cm³.
3. The volume is calculated using the formula Volume=MassDensityVolume = \frac{Mass}{Density}

STEP 2

First, we need to find the volume of glycerol the student should pour out. We can do this by dividing the mass of glycerol by its density.
Volume=MassDensityVolume = \frac{Mass}{Density}

STEP 3

Now, plug in the given values for the mass and density to calculate the volume.
Volume=65.0g1.26g/cm³Volume = \frac{65.0\, g}{1.26\, g/cm³}

STEP 4

Calculate the volume of glycerol the student should pour out.
Volume=65.0g1.26g/cm³=51.58730158730159cm³Volume = \frac{65.0\, g}{1.26\, g/cm³} =51.58730158730159\, cm³

STEP 5

Round the volume to3 significant digits.
Volume=51.cm³Volume =51.\, cm³The student should pour out51. cm³ of glycerol.

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