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Math

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PROBLEM

A company determined that the marginal cost, C(x)C^{\prime}(x) of producing the xx th unit of a product is given by C(x)=x34xC^{\prime}(x)=x^{3}-4 x. Find the total cost function CC, assuming that C(x)C(x) is in dollars and that fixed costs are \(\) 8000$.

STEP 1

1. The marginal cost function is given by C(x)=x34x C^{\prime}(x) = x^3 - 4x .
2. The fixed cost is $8000.
3. We need to find the total cost function C(x) C(x) .

STEP 2

1. Integrate the marginal cost function to find the total cost function C(x) C(x) .
2. Determine the constant of integration using the fixed cost information.
3. Write the complete expression for the total cost function C(x) C(x) .

STEP 3

Integrate the marginal cost function C(x)=x34x C^{\prime}(x) = x^3 - 4x to find C(x) C(x) :
C(x)=(x34x)dx C(x) = \int (x^3 - 4x) \, dx

STEP 4

Perform the integration:
C(x)=x3dx4xdx C(x) = \int x^3 \, dx - \int 4x \, dx C(x)=x442x2+C0 C(x) = \frac{x^4}{4} - 2x^2 + C_0 where C0 C_0 is the constant of integration.

STEP 5

Use the fixed cost information to determine the constant of integration. Given that the fixed cost is $8000, we have:
C(0)=8000 C(0) = 8000 Substitute x=0 x = 0 into the total cost function:
C(0)=0442(0)2+C0=8000 C(0) = \frac{0^4}{4} - 2(0)^2 + C_0 = 8000 C0=8000 C_0 = 8000

SOLUTION

Substitute C0=8000 C_0 = 8000 back into the expression for C(x) C(x) :
C(x)=x442x2+8000 C(x) = \frac{x^4}{4} - 2x^2 + 8000 The total cost function C(x) C(x) is:
C(x)=x442x2+8000 C(x) = \frac{x^4}{4} - 2x^2 + 8000

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