Math Snap
PROBLEM
A dart is thrown at 11.6 m/s and hits the board in 0.131 s. Find the distance to the board and how far below the bullseye it hit.
STEP 1
Assumptions1. The initial velocity of the dart is
. The dart hits the board after0.131 s3. The dart is thrown directly at the bullseye, so the initial vertical displacement is04. The acceleration due to gravity is 9.8 \mathrm{~m/s^} (downwards)
5. The dart follows a parabolic trajectory due to gravity
STEP 2
First, we need to find the horizontal distance to the board. Since there are no horizontal forces acting on the dart after it is thrown, it will maintain a constant horizontal velocity. We can find the horizontal distance by multiplying the horizontal velocity by the time it takes to hit the board.
STEP 3
Now, plug in the given values for the velocity and time to calculate the distance.
STEP 4
Calculate the distance to the board.
STEP 5
Next, we need to find how far below the bullseye the dart hit. We can do this by using the equation of motion for vertical displacement under constant acceleration (gravity).
STEP 6
Since the dart is thrown directly at the bullseye, the initial vertical velocity is0. Plug in the values for time and gravity to calculate the vertical displacement.
SOLUTION
Calculate the vertical displacement.
The negative sign indicates that the dart hit below the bullseye.
a. The board is1.52 m away.
b. The dart hit0.084 m below the bullseye.