QuestionFind the $z$ -score for a 90-pound dog given an average weight of 84 pounds and a standard deviation of 4 pounds.

Studdy Solution

STEP 1

Assumptions1. The average weight of a dog is84 pounds. The standard deviation is4 pounds3. The weight of the dog in question is90 pounds4. The weight of dogs is normally distributed

STEP 2

The $z$ -score is a measure of how many standard deviations an element is from the mean. It is calculated using the following formula $z = \frac{X - \mu}{\sigma}$ where- $X$ is the value of the element- $\mu$ is the mean- $\sigma$ is the standard deviation

STEP 3

Now, plug in the given values for $X$ , $\mu$ , and $\sigma$ to calculate the $z$ -score.
$z = \frac{90 -84}{}$

STEP 4

Calculate the $z$ -score.
$z = \frac{90 -84}{4} =1.$ So, the $z$ -score for a dog that weighs90 pounds is1.. The correct answer is (b)1.50.

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