Math

QuestionA drug uses 3 mL of compound A for every 5 mL of compound B. How much A is needed for 544 mL of the drug?

Studdy Solution

STEP 1

Assumptions1. The drug is made from only two ingredients compound A and compound B. . There are3 milliliters of compound A used for every5 milliliters of compound B.
3. The chemist wants to make544 milliliters of the drug.
4. The ratio of compound A to compound B is constant for any amount of the drug.

STEP 2

We need to find the total amount of compound A needed to make544 milliliters of the drug. We can start by finding the ratio of compound A to the total amount of the drug.
RatioA=CompoundACompoundA+CompoundBRatio_{A} = \frac{Compound_{A}}{Compound_{A} + Compound_{B}}

STEP 3

Now, plug in the given values for compound A and compound B to find the ratio.
RatioA=3ml3ml+5mlRatio_{A} = \frac{3 ml}{3 ml +5 ml}

STEP 4

Calculate the ratio of compound A to the total amount of the drug.
RatioA=3ml8mlRatio_{A} = \frac{3 ml}{8 ml}

STEP 5

Now that we have the ratio of compound A, we can find the amount of compound A needed to make544 milliliters of the drug. We do this by multiplying the total amount of the drug by the ratio of compound A.
AmountA=TotaldrugamounttimesRatioAAmount_{A} = Total\, drug\, amount \\times Ratio_{A}

STEP 6

Plug in the values for the total drug amount and the ratio of compound A to calculate the amount of compound A.
AmountA=544mltimes3ml8mlAmount_{A} =544 ml \\times \frac{3 ml}{8 ml}

STEP 7

Calculate the amount of compound A needed.
AmountA=544mltimes3mlml=204mlAmount_{A} =544 ml \\times \frac{3 ml}{ ml} =204 mlThe chemist needs204 milliliters of compound A to make544 milliliters of the drug.

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