PROBLEM
A golf ball is hit at 130 ft/s at 45∘. Find height h(100) using h(x)=1302−32x2+x.
STEP 1
Assumptions1. The initial velocity of the golf ball is130 feet per second.
. The golf ball is hit at an angle of 45∘ to the horizontal.
3. The height h of the golf ball is given by the function h(x)=130−32x+x where x is the horizontal distance that the golf ball has traveled.
STEP 2
To find the height of the golf ball after it has traveled100 feet, we need to substitute x=100 into the given function.
h(100)=1302−32×1002+100
STEP 3
First, calculate the square of100.
1002=10000
STEP 4
Substitute 1002 into the equation.
h(100)=1302−32×10000+100
STEP 5
Calculate the product of -32 and10000.
−32×10000=−320000
STEP 6
Substitute −32×10000 into the equation.
h(100)=1302−320000+100
STEP 7
Next, calculate the square of130.
1302=16900
STEP 8
Substitute 1302 into the equation.
h(100)=16900−320000+100
STEP 9
Calculate the division of -320000 by16900.
16900−320000≈−18.93
STEP 10
Substitute 16900−320000 into the equation.
h(100)=−18.93+100
SOLUTION
Calculate the sum of -18.93 and100.
−18.93+100=81.07The height of the golf ball after it has traveled100 feet is approximately81.07 feet.
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