QuestionA hamburger shop sold 291 total burgers, with cheeseburgers being twice the hamburgers. Find the number of hamburgers sold.

Studdy Solution

STEP 1

Assumptions1. The total number of hamburgers and cheeseburgers sold is291. . The number of cheeseburgers sold is two times the number of hamburgers sold.

STEP 2

Let's denote the number of hamburgers sold as $h$ and the number of cheeseburgers sold as $c$ . We know from the problem that $c =2h$ and $h + c =291$ .

STEP 3

We can substitute $c$ from the first equation into the second equation to solve for $h$ .
$h +2h =291$

STEP 4

Combine like terms on the left side of the equation.
$3h =291$

STEP 5

To find the value of $h$ , divide both sides of the equation by3.
$h = \frac{291}{3}$

STEP 6

Calculate the value of $h$ .
$h = \frac{291}{3} =97$ So,97 hamburgers were sold on Friday.

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QuestionA hamburger shop sold 291 total burgers, with cheeseburgers being twice the hamburgers. Find the number of hamburgers sold.

Studdy Solution

STEP 1

Assumptions1. The total number of hamburgers and cheeseburgers sold is291. . The number of cheeseburgers sold is two times the number of hamburgers sold.

STEP 2

Let's denote the number of hamburgers sold as $h$ and the number of cheeseburgers sold as $c$ . We know from the problem that $c =2h$ and $h + c =291$ .

STEP 3

We can substitute $c$ from the first equation into the second equation to solve for $h$ .
$h +2h =291$

STEP 4

Combine like terms on the left side of the equation.
$3h =291$

STEP 5

To find the value of $h$ , divide both sides of the equation by3.
$h = \frac{291}{3}$

STEP 6

Calculate the value of $h$ .
$h = \frac{291}{3} =97$ So,97 hamburgers were sold on Friday.

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QuestionA hamburger shop sold 291 total burgers, with cheeseburgers being twice the hamburgers. Find the number of hamburgers sold.

Studdy Solution

STEP 1

Assumptions1. The total number of hamburgers and cheeseburgers sold is291. . The number of cheeseburgers sold is two times the number of hamburgers sold.

STEP 2

Let's denote the number of hamburgers sold as hhh and the number of cheeseburgers sold as ccc. We know from the problem that c=2hc =2hc=2h and h+c=291h + c =291h+c=291.

STEP 3

We can substitute ccc from the first equation into the second equation to solve for hhh.h+2h=291h +2h =291h+2h=291

STEP 4

Combine like terms on the left side of the equation.3h=2913h =2913h=291

STEP 5

To find the value of hhh, divide both sides of the equation by3.h=2913h = \frac{291}{3}h=3291​

STEP 6

Calculate the value of hhh.h=2913=97h = \frac{291}{3} =97h=3291​=97So,97 hamburgers were sold on Friday.

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Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

Let's denote the number of hamburgers sold as $h$ and the number of cheeseburgers sold as $c$ . We know from the problem that $c =2h$ and $h + c =291$ .

We can substitute $c$ from the first equation into the second equation to solve for $h$ .
$h +2h =291$

Combine like terms on the left side of the equation.
$3h =291$

To find the value of $h$ , divide both sides of the equation by3.
$h = \frac{291}{3}$

Calculate the value of $h$ .
$h = \frac{291}{3} =97$ So,97 hamburgers were sold on Friday.