Math  /  Algebra

QuestionA hardware store rents vacuum cleaners that customers may use for part of a day before returning. The function f(x)=6x+14f(x)=6 x+14 models the total rental cost of a vacuum cleaner.
Which is a reasonable domain for the function? A. 14<x<3214<x<32 B. 0<x<250<x<25 C. 0<x<120<x<12 D. 14<x<8614<x<86

Studdy Solution

STEP 1

What is this asking? What are the reasonable values for xx (part of a day) given the total rental cost, f(x)f(x), of a vacuum cleaner? Watch out! Don't mix up the domain (input values of xx) and the range (output values of f(x)f(x)).
We're looking for reasonable values of xx, not f(x)f(x)!

STEP 2

1. Understand the function
2. Analyze the answer choices

STEP 3

Alright, so we've got this function f(x)=6x+14f(x) = 6x + 14, where f(x)f(x) is the **total rental cost** in $\$ and xx represents the **fraction of a day** the vacuum cleaner is rented for.

STEP 4

Let's break it down!
The 1414 represents a **fixed cost**, like a base fee just for renting the vacuum cleaner, regardless of how long you use it.
The 6x6x part represents a **variable cost** that depends on how long you rent it for.
The 66 is the **rate of change**, meaning it costs $6\$6 for each additional fraction of a day you rent the vacuum.

STEP 5

Since xx represents a fraction of a day, it must be between 00 and 11.
If x=0x=0, that means you didn't rent it at all, and if x=1x=1 you rented it for the whole day.
Any value between 00 and 11 represents a fraction of a day.

STEP 6

Let's look at the answer choices and see which one makes sense for our fraction of a day, xx.

STEP 7

Answer choice A, 14<x<3214 < x < 32, doesn't make sense because xx can't be greater than 11.
Remember, xx is a **fraction of a day**.

STEP 8

Answer choice B, 0<x<250 < x < 25, also doesn't work because xx can't be greater than 11.

STEP 9

Answer choice C, 0<x<120 < x < 12, is closer, but still not quite right.
While the lower bound of 00 is correct, the upper bound of 1212 is too high. xx can't be greater than 11.

STEP 10

Answer choice D, 14<x<8614 < x < 86, has the same issue – both bounds are way too high!

STEP 11

Since none of the given options are correct, let's determine a reasonable domain.
We know xx should be between 00 and 11 inclusive, so a reasonable domain would be 0x10 \le x \le 1.
If we must choose from the given options, C is the closest, but we need to adjust it to 0<x10 < x \le 1.
If we can't rent for a full day (x=1x=1), then 0<x<10 < x < 1 would be the most accurate representation.

STEP 12

The most reasonable domain for this function, given that xx represents a fraction of a day, is 0<x10 < x \le 1 if we can rent for a full day, or 0<x<10 < x < 1 if we can only rent for part of a day.
Since we have to choose, and option C is the closest, we'll choose C and keep in mind it should really be 0<x<10 < x < 1.

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