QuestionFind the point-slope formula inputs for a line through $(3,5)$ with slope -2: $y-5=-2(x-[?])$ .

Studdy Solution

STEP 1

Assumptions1. We have a line that intersects the point $(3,5)$ . . The slope of the line is -.
3. We are using the point-slope form of a line, which is $y - y1 = m(x - x1)$ , where $(x1, y1)$ is a point on the line and $m$ is the slope of the line.

STEP 2

The point-slope formula requires the coordinates of a point on the line and the slope of the line. We already have these values.

STEP 3

The point on the line is $(3,5)$ . So, $x1 =3$ and $y1 =5$ .

STEP 4

The slope of the line is -2. So, $m = -2$ .

STEP 5

Now, we can plug these values into the point-slope formula.
$y - y1 = m(x - x1)$

STEP 6

Substitute $y1 =5$ , $m = -2$ , and $x1 =3$ into the equation.
$y -5 = -2(x -3)$

STEP 7

So, the inputs to the point-slope formula are $y1 =5$ , $m = -2$ , and $x1 =3$ .

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QuestionFind the point-slope formula inputs for a line through $(3,5)$ with slope -2: $y-5=-2(x-[?])$ .

Studdy Solution

STEP 1

Assumptions1. We have a line that intersects the point $(3,5)$ . . The slope of the line is -.
3. We are using the point-slope form of a line, which is $y - y1 = m(x - x1)$ , where $(x1, y1)$ is a point on the line and $m$ is the slope of the line.

STEP 2

The point-slope formula requires the coordinates of a point on the line and the slope of the line. We already have these values.

STEP 3

The point on the line is $(3,5)$ . So, $x1 =3$ and $y1 =5$ .

STEP 4

The slope of the line is -2. So, $m = -2$ .

STEP 5

Now, we can plug these values into the point-slope formula.
$y - y1 = m(x - x1)$

STEP 6

Substitute $y1 =5$ , $m = -2$ , and $x1 =3$ into the equation.
$y -5 = -2(x -3)$

STEP 7

So, the inputs to the point-slope formula are $y1 =5$ , $m = -2$ , and $x1 =3$ .

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QuestionFind the point-slope formula inputs for a line through (3,5)(3,5)(3,5) with slope -2: y−5=−2(x−[?])y-5=-2(x-[?])y−5=−2(x−[?]).

Studdy Solution

STEP 1

Assumptions1. We have a line that intersects the point (3,5)(3,5)(3,5). . The slope of the line is -.3. We are using the point-slope form of a line, which is y−y1=m(x−x1)y - y1 = m(x - x1)y−y1=m(x−x1), where (x1,y1)(x1, y1)(x1,y1) is a point on the line and mmm is the slope of the line.

STEP 2

The point-slope formula requires the coordinates of a point on the line and the slope of the line. We already have these values.

STEP 3

The point on the line is (3,5)(3,5)(3,5). So, x1=3x1 =3x1=3 and y1=5y1 =5y1=5.

STEP 4

The slope of the line is -2. So, m=−2m = -2m=−2.

STEP 5

Now, we can plug these values into the point-slope formula.y−y1=m(x−x1)y - y1 = m(x - x1)y−y1=m(x−x1)

STEP 6

Substitute y1=5y1 =5y1=5, m=−2m = -2m=−2, and x1=3x1 =3x1=3 into the equation.y−5=−2(x−3)y -5 = -2(x -3)y−5=−2(x−3)

STEP 7

So, the inputs to the point-slope formula are y1=5y1 =5y1=5, m=−2m = -2m=−2, and x1=3x1 =3x1=3.

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QuestionFind the point-slope formula inputs for a line through $(3,5)$ with slope -2: $y-5=-2(x-[?])$ .

Assumptions1. We have a line that intersects the point $(3,5)$ . . The slope of the line is -.
3. We are using the point-slope form of a line, which is $y - y1 = m(x - x1)$ , where $(x1, y1)$ is a point on the line and $m$ is the slope of the line.

The point on the line is $(3,5)$ . So, $x1 =3$ and $y1 =5$ .

The slope of the line is -2. So, $m = -2$ .

Now, we can plug these values into the point-slope formula.
$y - y1 = m(x - x1)$

Substitute $y1 =5$ , $m = -2$ , and $x1 =3$ into the equation.
$y -5 = -2(x -3)$

So, the inputs to the point-slope formula are $y1 =5$ , $m = -2$ , and $x1 =3$ .