QuestionFind the equation of the line in point-slope form using the point $(-5,1)$ with slope $m=2$ . $y-1=2(x-[?])$

Studdy Solution

STEP 1

Assumptions1. The line intersects the points $(-5,1)$ and $(-,7)$ . . The slope of the line $m$ is.
3. We are asked to write an equation in point-slope form using the point $(-5,1)$ .

STEP 2

The point-slope form of a linear equation is given by the formula $y - y1 = m(x - x1)$ where $(x1, y1)$ is a point on the line and $m$ is the slope of the line.

STEP 3

We are given the point $(-5,1)$ , so we can substitute $x1 = -5$ and $y1 =1$ into the point-slope form equation.
$y -1 = m(x - (-5))$

STEP 4

We are given that the slope $m$ is2, so we can substitute $m =2$ into the equation.
$y -1 =2(x - (-))$

STEP 5

implify the equation by removing the double negative in the term $x - (-5)$ .
$y -1 =2(x +5)$ This is the equation of the line in point-slope form using the point $(-5,1)$ and slope $m=2$ .

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QuestionFind the equation of the line in point-slope form using the point $(-5,1)$ with slope $m=2$ . $y-1=2(x-[?])$

Studdy Solution

STEP 1

Assumptions1. The line intersects the points $(-5,1)$ and $(-,7)$ . . The slope of the line $m$ is.
3. We are asked to write an equation in point-slope form using the point $(-5,1)$ .

STEP 2

The point-slope form of a linear equation is given by the formula $y - y1 = m(x - x1)$ where $(x1, y1)$ is a point on the line and $m$ is the slope of the line.

STEP 3

We are given the point $(-5,1)$ , so we can substitute $x1 = -5$ and $y1 =1$ into the point-slope form equation.
$y -1 = m(x - (-5))$

STEP 4

We are given that the slope $m$ is2, so we can substitute $m =2$ into the equation.
$y -1 =2(x - (-))$

STEP 5

implify the equation by removing the double negative in the term $x - (-5)$ .
$y -1 =2(x +5)$ This is the equation of the line in point-slope form using the point $(-5,1)$ and slope $m=2$ .

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QuestionFind the equation of the line in point-slope form using the point (−5,1)(-5,1)(−5,1) with slope m=2m=2m=2. y−1=2(x−[?])y-1=2(x-[?])y−1=2(x−[?])

Studdy Solution

STEP 1

Assumptions1. The line intersects the points (−5,1)(-5,1)(−5,1) and (−,7)(-,7)(−,7). . The slope of the line mmm is.3. We are asked to write an equation in point-slope form using the point (−5,1)(-5,1)(−5,1).

STEP 2

The point-slope form of a linear equation is given by the formulay−y1=m(x−x1)y - y1 = m(x - x1)y−y1=m(x−x1)where (x1,y1)(x1, y1)(x1,y1) is a point on the line and mmm is the slope of the line.

STEP 3

We are given the point (−5,1)(-5,1)(−5,1), so we can substitute x1=−5x1 = -5x1=−5 and y1=1y1 =1y1=1 into the point-slope form equation.y−1=m(x−(−5))y -1 = m(x - (-5))y−1=m(x−(−5))

STEP 4

We are given that the slope mmm is2, so we can substitute m=2m =2m=2 into the equation.y−1=2(x−(−))y -1 =2(x - (-))y−1=2(x−(−))

STEP 5

implify the equation by removing the double negative in the term x−(−5)x - (-5)x−(−5).y−1=2(x+5)y -1 =2(x +5)y−1=2(x+5)This is the equation of the line in point-slope form using the point (−5,1)(-5,1)(−5,1) and slope m=2m=2m=2.

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QuestionFind the equation of the line in point-slope form using the point $(-5,1)$ with slope $m=2$ . $y-1=2(x-[?])$

Assumptions1. The line intersects the points $(-5,1)$ and $(-,7)$ . . The slope of the line $m$ is.
3. We are asked to write an equation in point-slope form using the point $(-5,1)$ .

The point-slope form of a linear equation is given by the formula $y - y1 = m(x - x1)$ where $(x1, y1)$ is a point on the line and $m$ is the slope of the line.

We are given the point $(-5,1)$ , so we can substitute $x1 = -5$ and $y1 =1$ into the point-slope form equation.
$y -1 = m(x - (-5))$

We are given that the slope $m$ is2, so we can substitute $m =2$ into the equation.
$y -1 =2(x - (-))$

implify the equation by removing the double negative in the term $x - (-5)$ .
$y -1 =2(x +5)$ This is the equation of the line in point-slope form using the point $(-5,1)$ and slope $m=2$ .