Math

QuestionFind the equation of a line with slope 1/31/3 that passes through the point (4,8)(-4, 8) in point-slope form.

Studdy Solution

STEP 1

Assumptions1. The slope of the line is 1/31 /3 . The line passes through the point (4,8)(-4,8)3. We need to write the equation of the line in point-slope form, which is given by yy1=m(xx1)y - y1 = m(x - x1), where mm is the slope of the line and (x1,y1)(x1, y1) is a point on the line.

STEP 2

First, let's write down the point-slope form of the line equation.
yy1=m(xx1)y - y1 = m(x - x1)

STEP 3

Now, plug in the given values for the slope and the point to write the equation of the line.
y8=13(x+)y -8 = \frac{1}{3}(x +)

STEP 4

This is the equation of the line in point-slope form that passes through the point (4,8)(-4,8) with a slope of 1/31 /3.
So, the equation of the line isy8=13(x+4)y -8 = \frac{1}{3}(x +4)

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