Math  /  Algebra

Question7 Mark for Review
A model predicts that the population of Springfield was 15,000 in 2005. The model also predicts that each year for the next 5 years, the population pp increased by 4%4 \% of the previous year's population. Which equation best represents this model, where xx is the number of years after 2005 , for x5x \leq 5 ? (A) p=0.96(15,000)xp=0.96(15,000)^{x} (B) p=1.04(15,000)xp=1.04(15,000)^{x} (C) p=15,000(0.96)xp=15,000(0.96)^{x} (D) p=15,000(1.04)xp=15,000(1.04)^{x} Question 7 of 22

Studdy Solution

STEP 1

1. The initial population of Springfield in 2005 is 15,000.
2. The population increases by 4% each year for the next 5 years.
3. We need to find an equation that models this population growth.
4. The variable x x represents the number of years after 2005, where x5 x \leq 5 .

STEP 2

1. Understand the concept of exponential growth.
2. Determine the growth factor.
3. Write the exponential growth equation.
4. Compare with given options.

STEP 3

Understand the concept of exponential growth.
In exponential growth, the population increases by a constant percentage each year. This means the population for each subsequent year is a fixed multiple of the previous year's population.

STEP 4

Determine the growth factor.
Since the population increases by 4% each year, the growth factor is 1+0.04=1.04 1 + 0.04 = 1.04 .

STEP 5

Write the exponential growth equation.
The general form of an exponential growth equation is p=p0(1+r)x p = p_0 \cdot (1 + r)^x , where p0 p_0 is the initial population, r r is the growth rate, and x x is the number of years.
For this problem, p0=15,000 p_0 = 15,000 , r=0.04 r = 0.04 , and the growth factor is 1.04 1.04 .
Thus, the equation is: p=15,000(1.04)x p = 15,000 \cdot (1.04)^x

STEP 6

Compare with given options.
The equation p=15,000(1.04)x p = 15,000 \cdot (1.04)^x matches option (D).
The correct equation is: p=15,000(1.04)x \boxed{p = 15,000 \cdot (1.04)^x}

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