Math  /  Algebra

QuestionA motorcyclist being monitored by radar accelerates at a constant rate from 0mph(v(0)=0)0 \mathrm{mph}(\mathrm{v}(0)=0) to 50 mph in 18 sec . How far has the motorcycle traveled after 18 sec? (Hint: Convert seconds to hours.)
After 18 sec , the motorcycle has traveled \square mi. (Simplify your answer. Type an integer or a fraction.)

Studdy Solution

STEP 1

1. The motorcyclist accelerates at a constant rate.
2. The initial velocity v(0)=0 v(0) = 0 mph.
3. The final velocity v(18)=50 v(18) = 50 mph.
4. Time duration is 18 seconds.
5. We need to convert seconds to hours for consistency in units.
6. We are to find the distance traveled in miles.

STEP 2

1. Convert time from seconds to hours.
2. Calculate the acceleration.
3. Use the kinematic equation to find the distance traveled.

STEP 3

Convert time from seconds to hours.
Since there are 3600 seconds in an hour, we convert 18 seconds to hours:
Time in hours=183600=1200 hours \text{Time in hours} = \frac{18}{3600} = \frac{1}{200} \text{ hours}

STEP 4

Calculate the acceleration.
The acceleration a a can be calculated using the formula:
a=ΔvΔt=v(18)v(0)Δt a = \frac{\Delta v}{\Delta t} = \frac{v(18) - v(0)}{\Delta t}
Substitute the known values:
a=50 mph0 mph1200 hours=50×200=10000 mph2 a = \frac{50 \text{ mph} - 0 \text{ mph}}{\frac{1}{200} \text{ hours}} = 50 \times 200 = 10000 \text{ mph}^2

STEP 5

Use the kinematic equation to find the distance traveled.
The distance d d traveled under constant acceleration can be found using the equation:
d=v0t+12at2 d = v_0 \cdot t + \frac{1}{2} a t^2
Substitute the known values:
d=01200+12×10000×(1200)2 d = 0 \cdot \frac{1}{200} + \frac{1}{2} \times 10000 \times \left(\frac{1}{200}\right)^2
d=12×10000×140000 d = \frac{1}{2} \times 10000 \times \frac{1}{40000}
d=1000080000 d = \frac{10000}{80000}
d=18 miles d = \frac{1}{8} \text{ miles}
After 18 seconds, the motorcycle has traveled 18 \boxed{\frac{1}{8}} miles.

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