QuestionFind a number $x$ such that $6x + 2 = 2 \times 19$ .

Studdy Solution

STEP 1

Assumptions1. A number is multiplied by6. The product is added to3. The sum is equal to the product of and19

STEP 2

Let's denote the unknown number as $x$ . The problem can be translated into the following equation $6x +2 =2 \\times19$

STEP 3

Calculate the product on the right side of the equation.
$2 \\times19 =38$ So, the equation becomes $6x +2 =38$

STEP 4

To isolate $x$ , we first need to get rid of the "+2" on the left side of the equation. We do this by subtracting2 from both sides of the equation.
$6x +2 -2 =38 -2$

STEP 5

Perform the subtraction operation on both sides.
$x =38 -2 =36$

STEP 6

Now, to solve for $x$ , we need to divide both sides of the equation by6.
$x = \frac{36}{6}$

STEP 7

Perform the division operation to find the value of $x$ .
$x = \frac{36}{6} =6$ The number is6.

Was this helpful?

QuestionFind a number $x$ such that $6x + 2 = 2 \times 19$ .

Studdy Solution

STEP 1

Assumptions1. A number is multiplied by6. The product is added to3. The sum is equal to the product of and19

STEP 2

Let's denote the unknown number as $x$ . The problem can be translated into the following equation $6x +2 =2 \\times19$

STEP 3

Calculate the product on the right side of the equation.
$2 \\times19 =38$ So, the equation becomes $6x +2 =38$

STEP 4

To isolate $x$ , we first need to get rid of the "+2" on the left side of the equation. We do this by subtracting2 from both sides of the equation.
$6x +2 -2 =38 -2$

STEP 5

Perform the subtraction operation on both sides.
$x =38 -2 =36$

STEP 6

Now, to solve for $x$ , we need to divide both sides of the equation by6.
$x = \frac{36}{6}$

STEP 7

Perform the division operation to find the value of $x$ .
$x = \frac{36}{6} =6$ The number is6.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionFind a number xxx such that 6x+2=2×196x + 2 = 2 \times 196x+2=2×19.

Studdy Solution

STEP 1

Assumptions1. A number is multiplied by6. The product is added to3. The sum is equal to the product of and19

STEP 2

Let's denote the unknown number as xxx. The problem can be translated into the following equation6x+2=2times196x +2 =2 \\times196x+2=2times19

STEP 3

Calculate the product on the right side of the equation.2times19=382 \\times19 =382times19=38So, the equation becomes6x+2=386x +2 =386x+2=38

STEP 4

To isolate xxx, we first need to get rid of the "+2" on the left side of the equation. We do this by subtracting2 from both sides of the equation.6x+2−2=38−26x +2 -2 =38 -26x+2−2=38−2

STEP 5

Perform the subtraction operation on both sides.x=38−2=36x =38 -2 =36x=38−2=36

STEP 6

Now, to solve for xxx, we need to divide both sides of the equation by6.x=366x = \frac{36}{6}x=636​

STEP 7

Perform the division operation to find the value of xxx.x=366=6x = \frac{36}{6} =6x=636​=6The number is6.

Get Studdy

Studdy solves anything!

Start learning now

Download Studdy AI Tutor now. Learn with ease and get all help you need to be successful at school.

QuestionFind a number $x$ such that $6x + 2 = 2 \times 19$ .

Let's denote the unknown number as $x$ . The problem can be translated into the following equation $6x +2 =2 \\times19$

Calculate the product on the right side of the equation.
$2 \\times19 =38$ So, the equation becomes $6x +2 =38$

To isolate $x$ , we first need to get rid of the "+2" on the left side of the equation. We do this by subtracting2 from both sides of the equation.
$6x +2 -2 =38 -2$

Perform the subtraction operation on both sides.
$x =38 -2 =36$

Now, to solve for $x$ , we need to divide both sides of the equation by6.
$x = \frac{36}{6}$

Perform the division operation to find the value of $x$ .
$x = \frac{36}{6} =6$ The number is6.