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Math Snap
PROBLEM
A. 2π B. 23π C. π D.undefined Q.27) The value of 4sin−1(195)+4cos−1(195)= A. π B. 21π C. 41π D. 2π
STEP 1
1. The problem involves inverse trigonometric functions. 2. The identity sin−1(x)+cos−1(x)=2π can be used for any x in the domain of the inverse sine and cosine functions.
STEP 2
1. Apply the identity for inverse trigonometric functions. 2. Simplify the expression using the identity. 3. Calculate the final value.
STEP 3
Recall the identity for inverse trigonometric functions: sin−1(x)+cos−1(x)=2πThis identity holds true for any x such that −1≤x≤1.
STEP 4
Apply the identity to the given expression: 4sin−1(195)+4cos−1(195)Using the identity: sin−1(195)+cos−1(195)=2πMultiply both sides of the identity by 4: 4(sin−1(195)+cos−1(195))=4×2π
SOLUTION
Simplify the expression: 4×2π=2πThe value of the expression is: 2π