Math

QuestionConvert 0.0833 lb of glucose (C6H12O6\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}) to mg. Use 1lb=453.6g1 \mathrm{lb}=453.6 \mathrm{g}.

Studdy Solution

STEP 1

Assumptions1. The person's average daily intake of glucose is0.0833 pound (lb). . We need to convert this mass to milligrams (mg).
3. The conversion factor is1 lb =453.6 g.

STEP 2

First, we need to convert the mass from pounds to grams using the given conversion factor.
Massingrams=MassinpoundstimesConversionfactorMass\, in\, grams = Mass\, in\, pounds \\times Conversion\, factor

STEP 3

Now, plug in the given values for the mass in pounds and the conversion factor to calculate the mass in grams.
Massingrams=0.0833lbtimes453.6g/lbMass\, in\, grams =0.0833\, lb \\times453.6\, g/lb

STEP 4

Calculate the mass in grams.
Massingrams=0.0833lbtimes453.6g/lb=37.77gMass\, in\, grams =0.0833\, lb \\times453.6\, g/lb =37.77\, g

STEP 5

Now that we have the mass in grams, we need to convert this to milligrams. We know that1 gram is equal to1000 milligrams.
Massinmilligrams=Massingramstimes1000mg/gMass\, in\, milligrams = Mass\, in\, grams \\times1000\, mg/g

STEP 6

Plug in the value for the mass in grams to calculate the mass in milligrams.
Massinmilligrams=37.77gtimes1000mg/gMass\, in\, milligrams =37.77\, g \\times1000\, mg/g

STEP 7

Calculate the mass in milligrams.
Massinmilligrams=37.77gtimes1000mg/g=37770mgMass\, in\, milligrams =37.77\, g \\times1000\, mg/g =37770\, mgThe person's average daily intake of glucose is37770 milligrams.

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