Math

Question Find the angle, distance traveled, and linear speed of a point P on a circle with radius r=4r=4 in, rotating at angular speed ω=π3\omega=\frac{\pi}{3} rad/min for t=9t=9 min.

Studdy Solution

STEP 1

Assumptions
1. The radius of the circle is r=4r = 4 inches.
2. The angular speed is ω=π3\omega = \frac{\pi}{3} radians per minute.
3. The time for which the ray OPOP is rotating is t=9t = 9 minutes.
4. The angle generated by point PP in time tt is denoted by θ\theta.
5. The distance traveled by point PP along the circle in time tt is denoted by ss.
6. The linear speed of point PP is denoted by vv.

STEP 2

To find the angle generated by point PP in time tt, we use the formula for angular displacement, which is the product of angular speed and time.
θ=ω×t\theta = \omega \times t

STEP 3

Now, plug in the given values for ω\omega and tt to calculate the angle θ\theta.
θ=π3×9\theta = \frac{\pi}{3} \times 9

STEP 4

Calculate the angle θ\theta.
θ=π3×9=3π\theta = \frac{\pi}{3} \times 9 = 3\pi
So the angle generated by PP in time tt is 3π3\pi radians.

STEP 5

To find the distance traveled by point PP along the circle in time tt, we use the formula for arc length, which is the product of the radius and the angle (in radians).
s=r×θs = r \times \theta

STEP 6

Plug in the values for rr and θ\theta to calculate the distance ss.
s=4×3πs = 4 \times 3\pi

STEP 7

Calculate the distance ss.
s=4×3π=12πs = 4 \times 3\pi = 12\pi
So the distance traveled by PP along the circle in time tt is 12π12\pi inches.

STEP 8

To find the linear speed of point PP, we use the formula for linear speed, which is the distance traveled divided by the time taken.
v=stv = \frac{s}{t}

STEP 9

Plug in the values for ss and tt to calculate the linear speed vv.
v=12π9v = \frac{12\pi}{9}

STEP 10

Simplify the expression for the linear speed vv.
v=12π9=4π3v = \frac{12\pi}{9} = \frac{4\pi}{3}
So the linear speed of PP is 4π3\frac{4\pi}{3} inches per minute.
The solutions are: (a) The angle generated by PP in time tt is 3π3\pi radians. (b) The distance traveled by PP along the circle in time tt is 12π12\pi inches. (c) The linear speed of PP is 4π3\frac{4\pi}{3} inches per minute.

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