Math

QuestionFind the width and length of a rectangular area fenced along a river, where length is 7 ft more than width and total fencing is 91 ft.

Studdy Solution

STEP 1

Assumptions1. The length of the fenced-in area is7 feet greater than the width. . The total amount of fencing to be used is91 feet.
3. The fenced-in area is a rectangle.
4. The river bank is one of the sides of the rectangle, so it does not need to be fenced.

STEP 2

Let's denote the width of the rectangle as ww and the length as ll. According to the problem, the length is7 feet greater than the width, so we can express the length as l=w+7l = w +7.

STEP 3

The total amount of fencing to be used is equal to the perimeter of the rectangle. However, since one side (the river bank) does not need to be fenced, the total amount of fencing will be equal to the sum of the lengths of the other three sides. This can be expressed as 2w+l=912w + l =91.

STEP 4

Now we have a system of two equations1. l=w+7l = w +7
2. 2w+l=912w + l =91

STEP 5

Substitute the expression for ll from the first equation into the second equation2w+(w+7)=912w + (w +7) =91

STEP 6

implify the equation3w+=913w + =91

STEP 7

Subtract7 from both sides of the equation to isolate 3w3w3w=9173w =91 -7

STEP 8

Calculate the right side of the equation3w=843w =84

STEP 9

Divide both sides of the equation by3 to solve for www=84/3w =84 /3

STEP 10

Calculate the value of www=28w =28

STEP 11

Now that we have the width, we can find the length by substituting w=28w =28 into the first equationl=w+7l = w +7

STEP 12

Substitute w=28w =28 into the equationl=28+7l =28 +7

STEP 13

Calculate the value of lll=35l =35The width of the fenced-in area is28 feet and the length is35 feet.

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